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Pum� Sel�ciion Prc�ed:ure <br /> A. Determine pump capaeity: <br /> Gravity Disttibution <br /> 1. Minim� use is 600 gallons per hour(10 gpm)to stay <br /> ahead of vWater use rate. <br /> 2. Maximum suggested for delivery to a�rop box of a home <br /> systern is 2,700 gallon per hour(45 gpm)to prevent build-up <br /> of pressure in the drop box. <br /> Pressure Distribution <br /> 3. <br /> a. The r�urriber of perforated laterals is 3. <br /> b. The perfoFat�on spacing will be 3 feet on center. <br /> c. Subtract 2 ft. from the rock layer length; <br /> SO-2 =48feet <br /> d. Determine the number of spac�s between perforations; <br /> by dividing 3.c by 3.b; <br /> 48/3 = 16 spaces <br /> e. 16 spaces + 1 = 17 perforations per lateral <br /> f. Multiply the 3.a and 3.e to determine <br /> the total number of perforations; <br /> 3 x 17 = S 1 total perforations <br /> g. Multiply 3.f and 0.74 to determine the gpm; <br /> 51 x 0.74 = 39 lans per minute <br /> SELECTED PUMP MINIMUM CAPACITY =39 GPM <br /> B. Determine the he�.d pressure req�tirements. <br /> l. Elevatian difference between the pump <br /> and the point of discharge is 9 fcet. � <br /> 2. Add 5 feet of head for pressure required at the <br /> manifold if this is a pressure distribution system. <br /> 3. Friction loss; <br /> a. Enter the friction loss multipIier from <br /> the table wit gpm & pipe diameter. <br /> 1.55 <br /> b. Determine the pipe length from the <br /> pump to the diseharge point. Add 25°ro <br /> to the pipe length for�tting loss. <br /> 50 x 1.25 =b3 feet <br /> c. Calculate the total friction loss by multiplying <br /> B.3a by B.3b and dividing by 100 and rounding up; <br /> (1.SSx63)/ 100=2feet <br /> 4. Calculate the total head required by totaling B.1, B.2, and B.3c; <br /> 9 + 5 + 2 = 16feetofhead <br /> TOTAL REQUIRED MINIMU1Vi HEAD IS 16 FEET. <br /> The pump installed must be able to deliver at least 39 gallons per minute with at <br /> least 16 feet of head. <br />