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1999-011516 - new septic
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45 Cristofori Circle - 31-118-23-43-0012
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1999-011516 - new septic
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Last modified
8/22/2023 4:32:50 PM
Creation date
5/24/2016 10:59:10 AM
Metadata
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Template:
x Address Old
House Number
45
Street Name
Cristofori
Street Type
Circle
Address
45 Cristofori Circle
Document Type
Septic
PIN
3111823430012
Supplemental fields
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, . <br /> Mo�nd Desi Worksh t <br /> A. Flow <br /> Estimated at 600 gal�ons per day(gpd) far a four bedroam dwelji��. <br /> B. Septic Tank Liquid Volumas <br /> # of sepiic tanks=2 capacity= 1000 gallon tanks <br /> Lift sta�ion capac�ty� 1000 � ��lans <br /> C. Soils (re€er to soils lag and percolation c�ata sheets that follow) <br /> 1. Depth to festricting layer=28" <br /> 2. Depth of percolation tests= 12" <br /> 3. Texture of'soils are Clav loam with a percolation rate of 45 minutesPer inch. <br /> 4. Land slo = 5% <br /> D. Rock Layer Dixnensions <br /> 1. Multiply flow rate by .83 to obtain required area of rock layer: A x 0.83 = <br /> 600 x .0.83 = S00 square feet <br /> 2. Rock bed width will be 7.5 feet <br /> 3. Length of rock layer is the square feet area/width = <br /> 500/7.S= 67 l'rneal fee� 6 feet added unto the existing rock bed. <br /> E. Rock Volume for the add:itional rock bed <br /> 1. Multiply the rock area by the rock depth to determine the cubic feet of rock: <br /> 45 x 1 =45 cubic feet <br /> 2. Divide the cubic f�et by 27 cu. Feet to determine the cubic yards: <br /> 45/27= 1.67 cubic yards <br /> 3. Muttiply the cubic yards by 1.4 to determine the weight of rock in tons: <br /> 1.67 x 1.4=2.3 tons of clean wash a re ate rock <br /> F. Abso mtiOn Width rExc son, o� xnnooF <br /> 'Y RATE 7E?CNRE PER ABSORPIlON WIDTH <br /> IN�I FI' TO UYER R'IDTfi <br /> >.OS Caa�c S�nd 1.20 1.00 <br /> 1. Percolation rate in the to 12" of soil is 45 m i. 91 ms �.°° 1.� '.°° <br /> P P a.,e s F��,o .� �.� <br /> Texture is clay loam. 6b�s �-^ o.� ►.s2 <br /> 16.b 30 l.omm .0.60 2.0 <br /> 311045 Silt[.o�m .O.SO 2.�0 <br /> 16 b 60 C l.omt 0.4� 2.67 <br /> 2. Select allowable soil loading rate from Table. �o � az. S.� <br /> 0.45 gal lons per day per s�uare foot of rock area. <»� �ry �m �� <br /> 3. Calculate the absorption width ratio by dividing the rock layer loading rate of 1_2 <br /> gpd/ft2 by allowable soil loading rate: <br /> 1.2/0.45 = 2.67 <br /> 4. Multiply the absorption width ratio by the rock tayer width to determine�he <br /> required absorption width; <br /> 2.67x 10 =27feet <br />
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