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1998-010743 - new septic system
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1120 Cox Farm Road - 27-118-23-31-0021
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1998-010743 - new septic system
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Last modified
8/22/2023 4:19:49 PM
Creation date
5/12/2016 3:11:29 PM
Metadata
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Template:
x Address Old
House Number
1120
Street Name
Cox Farm
Street Type
Road
Address
1120 Cox Farm Road
Document Type
Septic
PIN
2711823310021
Supplemental fields
ProcessedPID
Updated
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E-19 <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW / D-7 <br /> � � Estimated(-� � � gpd (see pages D-7 or I-3,4,5) �*'""'ID S��°",�'"�°"'°°'°°' <br /> rawecn rrve oF r�sio�cc <br /> or measured gpd. �'"°°'b = II � � <br /> Z 30O �S �EO 601G <br /> S 490 300 210 � <br /> s soo s�s zss `a'"' <br /> i� <br /> B. SEPTIC TAIVK LIQUID VOLUMES a � �� � T'�.�' <br /> I � '�}� gallons (see pages C-3 or G5) ° �� � � �- <br /> �=� <br /> C-3 <br /> � SEPTIC TANK CAPACITIES, IN GALLONS <br /> � C. SOILS (refer to site evaluation) �,, r-- <br /> 1. Depth to restricting layer = �- r inches �°� � `�� <br /> .�ItlOY. UW�O G..CI, ��,.�..� <br /> 2. Depth of percolation test�= �� inches ,�„n. ,.. ,,,. <br /> 3. Percolation rate �`�-��-� mpi �°�� ���� ���• <br /> 4. Land slope �� % '�' '�°• "`° <br /> �.��. _... �... <br /> D. ROCK LAYER DIMINSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> f � <br /> ��� gpd x 0.83 sq. ft./gpd =y ��`" sq. ft.`�� "' ` <br /> � 2. Select width of rock layer (10 feet or less) _ �� ft. <br /> ` 3. Length of rock layer = area-�-width = <br /> I a . . _ . �- <br /> � sq. ft. i ' ft. ft. Rock Bed <br /> f•f•J•1•t•l•l•t•r•1•f•t•1•t•1 <br /> I ti•ti•ti•ti•t•ti•ti•1�•'�•1•ti•ti•'L•ti•ti• <br /> ti�'ti�ti�4:tif��ti�ti�ti�ti:ti�ti:1�:ti:ti? idth SIO ft. <br /> - tifti:ti1ti:tif 1�:1:ti:+yrti:i:�.:ti:ti�ti: <br /> . .r•l•r•f•1•f•l•J•l•t.1•1.1.1•J <br /> i E. ROCK VOLUME � ��g� --' , <br /> 1. Multipl�rock area by rock depth to get cubic feet of roc�c; <br /> IS `�� sq: ft. x �� ft. _ � cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; � <br /> � cu. ft. i 27= ,.= '' cu. yd. <br /> � 3. Multi pl y cubic yards b y 1.4 to get wei ght of rock in tons; <br /> , <br /> 1 ' ' cu. yd. x 1.4 ton/cu. yd. = tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is�7�'-��=�mpi E-16 , <br /> 2. Select allowable soil loading rate from table on page E-16; u•p•••.••«���a�•�� � <br /> ' F ........ �....r......�. ! <br /> ,, C? gpd/ft2 <br /> 3. Calculate adsorption width ratio by dividing rock layer """" °""" """ ""�" `"'r""""" � <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ��'� � '� ��� ��� '�� ' <br /> . .,. o.�. ,.x �.,, ,.,. <br /> �� •�o o.w o.N :.s� x.oa <br /> 1.20 gpd/ft2-�- � $Pd��2 = '` „ .. o.,� o..� _.� ...o � <br /> �l� .. :.a o... o.�= ,.�� _.., , <br /> �� •ue o.z� oa� o.0 e.ae - <br /> Check this value on page E-16. � <br /> 4. Multiply adsorption width ratio by rock layer width to get � <br /> required adsorption width; ; k <br /> �. '�D x /:J ft- d-� ft ' <br /> . , <br /> 1 <br /> � <br /> � <br /> � <br /> , <br /> : <br /> ; <br />
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