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MOUND DESIGN WORKSHEET .. <br /> �� (For Flows up to 1200 gpd) <br /> A: �,Qw Estimu�d Sewage Flow in Gallons per Day(gpd) <br /> Est'imated 6 0o gpd � x;,R,� <br /> or measured x 1.5 = $Pd• s�°�� �'�I 'IYv�II 'n'P�III �y��v � <br /> z . aoo �zs .1so. . �,, <br /> 3 450 300 218 �t <br /> B. SEPTTC TANK LIQUID VOLUMES 4 s�s a.s6 '� <br /> /2,s o allons t /000 G�cc a,✓ 5 �so 4so Zsa ""�°" . <br /> g ZN� T/N,r 6 900 525 332 � <br /> f /250 G./GtG,✓ /�NMI/Nrr T,�NK. • � 1� � 370 �°� <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) N,�� ,� ,�m � <br /> 1. 'Depth to restricting layer= 2 `� inches �.:"� `�`''"" <br /> 2. Depth of percolation tests =_ /y' inches 8�� � �' <br /> 3. Percolation rate /.�. O mpi za� �so �.,u <br /> 4. Land slope_ ,� qo s a 6 i;oo 2� <br /> �a s �,000 s.000 <br /> wa 9 See fi�.C-6 (x 1S) . <br /> D. ROCK LAYER DII�iENSIONS ' <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = _ . <br /> 60o gpd x 0.83 sq.ft../gpd = Sa.o Sq, ft: <br /> 2. Select width of rock layer(10 feet or less) _ /O ft. <br /> 3. Length of rock layer=area+width= Rock Bed <br /> 0 o sq.ft.+ /o ft. = So ft. � <br /> �•�•�•ti.�.ti.�.�.�.�.�.ti.,.ti.,.,.ti <br /> l•l r r./.�.f I � � t� f t f l . . <br /> � ti.ti.ti.ti.�.ti.y.ti.t.t•�.`.5..ti.�.` <br /> tir•f•l.f.l.d•J.f•! t•t•f.f.f.f.f. <br /> •�•ti•�.�.�.ti•ti.�•�.ti.ti.ti.ti.ti.ti.` idth 510 ft. <br /> f•f.f.f.r.r.r.f.f.f.f.f.r.r.r.f. <br /> '\ftiftiftifti•ti.ti.ti.ti.ti,ti.�,�,ti,ti,ti,ti . <br /> f�f•/•f•f.f.r.r.r.f.f.f, <br /> E. ROCK VOLUME �- Length --+ <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �`� <br /> soo sq.ft.x / ft. =S�a cu. ft. , <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards, <br /> Soo cu,ft. +27= / ,S cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; � <br /> ✓�.S cu.yd.x 1.4 ton/cu.yd. = 2 6 tons. . . _ <br /> F." ADSORI'TTON WIDTH <br /> Abao 'an►Yidth Sirin Tible <br /> 1. Percolation rate in top 12 inches of soil is �.3 Ompi P�,,,�,�,� ��,. R�,� <br /> , Mu,uce.prr inch Soil Texture r��w=• �` <br /> (mpJ �.. <br /> 2. Select allowable soil loading rate�from table; Faster than 0.1 oa�sana 12o i.�'�oo� <br /> - �.fF 0. 60 �d/f� o.lto5 Sand 120 1.00 <br /> 0.1 to 5 Fine Sand" 0•b� 2.00 <br /> 6 to 15 ndy Loam 0.79 1S2 <br /> 3. Calculate adso hon width ratio b dividin rock la er 16 co so t,o�„ o.bo 2.00 <br /> � • Y g �' 31 to 45 Silt Loam OSO 2.40 <br /> load.ing rate of 1.2a gpd/ft2 by allowable soil loading rate; �to�o Clay Loam 0.45 2.67 <br /> 1.20 gpd/ft2+ o. 6o gpd/ft�= Z n 61 eo 12o Clay 024 5.00 <br /> • Slower than 120 CTa - <br /> "Shc 1»vin�509i oe mare af EL+e ar vay'Rne�and. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; � <br /> Z .o x �o ft= 2o ft <br /> � , <br /> . ! <br />