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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A� FLOW , , <br /> Gstimatcd Sewage Flows in Galluns ps Jay <br /> Estimated '� O gpd (see pa�es D-7 or I-3, 4, 5) ,��m�� �°�� <br /> or measured — gpd x 1.5 = --- ��°�mi Typc I Typc:II Typc 111 TI� <br /> B. SEPTIC TANK LIQUID VOLUl�1ES 3 asa 3� zga o� <br /> 4 600 375 256 ���� <br /> 1-laSo �-- I-/o0 0 gallons (see pa�es C-3 or C-5) s �so �so �� ;, <br /> 6 9W 525 332 T>v<<. <br /> 7 ]O50 I 600 370 n°f <br /> C. SOILS (refer to site evaluation) s i2oo 6�s aos �d�,d <br /> 1. Depth ±o rest.lCtiTlo layer = _Iy �'f� �O �� lI;Ci1��� s�v�KT.�,4c.�..�i:�t��x.n„��, <br /> i <br /> 2. Depth of percolation tests = ) � '` inches ���m= "`°�"J�`'�"�I`.''u J";"`::y'";" <br /> Cspe..:y g<ro.,be di..;;�,.1 <br /> 3. Percolation rate � . �! m i zo�kSf ,�o ��u <br /> � 3wa �an txb <br /> 4. Land slope 3 °l0 4or6 ,�p z� <br /> �,s a 9 zou� x,w <br /> ovor 9 .__._ <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = , <br /> '� J gpd x 0.83 sq. ft./gpd = !��� sq. ft.�-i�'-_ _��'L}`� <br /> 2. Select width of rock layer (10 feet or less) _ / D ft. <br /> 3. Length of rock layer = Area = Width = <br /> ��sq. ft. i _L ft. _ �Sl ft. Rock Bed <br /> f'�'f'f'f•f•t•f•:�t•f�l:f�t�f <br /> 5�••.•'.•ti•ti•'�•ti••.••.••.••.•'.•ti•ti••.• <br /> tirtifti�ti.tirtif f r r r•r r ��r•: <br /> �+•ti�ti �; •. ti•ti •. 'Vidth <_]0 ft. <br /> .f�f�f.r.f.f.f,f.f�f::,f�:;r,f <br /> •. . ti•ti.ti.ti.ti.. <br /> E. ROCK VOLUME .:.f:•.:.:.r.:.::::f:f::::`::•: <br /> �— Length ---� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> l��L sq. ft. x 1.v7' ft. = Z cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 71�d cu. ft. s 27 = a2_cu. yd. <br /> 3. MulHply cubic yards by 1.4 to get weight of rock in tons; <br /> a'1 cu. yd. x 1.4 ton/cu. yd. _� tons. <br /> F. ADSORPTION WIDTH G L�`-{ Lo Y}vv� <br /> 1. Percolation rate in top 12 inches of soil is L '�d mpi Absorption Width Sizing 7'ablc <br /> 2. Select allowable soil loadin rate from table on a e E-• PercolationRalc ca��o�s Ratioof <br /> p g � in MinWes per Soil Texwre per day per Absorp�ion widtb <br /> �.,L gpd/ft� �^�h cMP,� square foa �o Rock Laycr <br /> w,d,n <br /> 3. Calculate adsorption wi�th ratio by dividing roc�c layer Facterthan0.1• c�s�„� .___ __.__ <br /> o.�ws se�a �.Zo i.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.��s•• Fine Sand•• o.�o z.�o <br /> 1.20 d/ft� . d/ft - �,,o � b�ois s,�ay�,,, 0.�9 isz <br /> � -'-1�gP Z— � 16 ro 30 L,oam 0.60 2.00 <br /> 31 to as silc Loam o.s9 z.�t0 <br /> Check this value on page E-16. ���o c�ay�, e�4s._: 2.�, <br /> 60 a 12[1 — Ciay—" " 0.24 S.W <br /> 4. Multiply adsorption width ratio by rock layer width to get Slower[han c�ay _____ _____ <br /> i�.. <br /> required adsorption width; <br /> a.c�� x�ft = .'� ft <br /> � <br />