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_ � � MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> � , <br /> A. FLOW Estimated Sewage Flows in Gallcx�s�xr d�y <br /> 4, 5) cRr�> <br /> Estimated��gpd (see pages D-7 or I-3, ,`�m�� , <br /> or measured d x 1.5 = - or Typc I Type]f Type il[ T�� <br /> g P I�e�iroom s 1 V <br /> B. SEPTIC TANK LIQUID VOLL�'fES Z 30o Zu �Ao <br /> 3 450 3(i0 218 � <br /> 4 600 375 256 °�`b` <br /> 1- )�`O �; t- 1 C c.� D gallons (see pag�s C-3 or C-�; s �so aso Z�a "';o' <br /> 6 9G0 525 332 Trr�i. <br /> 7 1050 600 370 fl" <br /> 8 1200 675 408 cd�a' <br /> C. SOILS (refer to site evaluation) ,, <br /> :.1 • � Scpl'e T.��4 C.y�.ciii��6�g.il..ns <br /> 1. D�pth to restrictinb laye: = 1 � :nc:��:s , <br /> � ,. , V�,unxr o( �1i��mi�m l.iyuiu L.quid c:+p:+��ity wl;;, <br /> 2. Depth of percolation tests = -- inclles ��.��f �.:,a�,y I g+rbagc�,.,,,,�� <br /> 3. Percolation rate I�-1 . �� Inpi z;�;� ;�, ;� <br /> 4. Land slope 3 % 4 or 6 ,�,�, z� <br /> �,s a 9 z000 woo <br /> o�«9 •.--- <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> ��v gpd x 0.83 sq. ft./gpd = ���, sq. ft.-t-�:;�� = ��%�+`� ' <br /> 2. Select width of rock layer (10 Eeet or less) _ > % ft. <br /> 3. Length of rock layer = Area = Width = <br /> ��-I sq. ft. � /0 ft. = 1�4� ft. Rock Bed <br /> f•t•f.l•f�f•f.r•l�f•l�l�l�l�l <br /> ti•'.•'.•ti•ti•ti•ti•ti•'.••. • •. ti•ti•ti• <br /> t•t•f•t•t•t•f•J•t•f�l.l•t•r•: <br /> ti•ti•ti•ti•ti•ti•ti•ti••.•ti•ti•ti•ti•ti•ti• idth _<IOft. <br /> •r;r;f•r•r•r•r•r•r•r;r;r;�.r:r <br /> . ti•ti.ti.ti.ti.. <br /> ��r•:•:.:•r•:•:�:�r�r�:�:::�r <br /> E. ROCK VOLUME ►-- �e„�th -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> ���sq. ft. x /-'��ft. _��cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �sl cu. ft. s 27 = �2 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �'1 cu. yd. x 1.4 ton/cu. yd. _ �� tons. <br /> F. ADSORPTTON WIDTH �U�`1' ��r''� <br /> 1. Percolation rate in top 12 inches of soil is �4.'� mpi Absorption Width Si�(ngTablc <br /> Percolation Rate Galbns Ratio of <br /> 2. Select allowable soil loadin�t, rate from table on page E-; in Minutes pu so��rrX��� per day per Absorplion width <br /> fnch(MPI) square foo[ to Rock Laya <br /> • ��_ gpd/ft� w,d�n <br /> 3. Calculate adsorption width ratio by dividing rock layer Fa�terthan0.1� c�s�,n ---- _____ <br /> o.�ws sa�a t.io i.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.��os•• Fine Sand•• o.�o z.�o <br /> �1 6 to 15 Sandy Loam 0.79 1.52 <br /> 1.20 gpd/ft�t .a � gpd/ftz= � , �i % . 16to30 �am o.� 2.��, <br /> 31 to as silt Loam o.50 z.40 <br /> Check this value on page E-16. ���o c�ay r�„ o.4s z.�� <br /> 60 to 120 Clay 0.24 S.W <br /> 4. Multiply adsorption width ratio by rock layer width to get Sli���an c�sy --- _____ <br /> required adsorption width; <br /> ? "� x 10 ft = %�:,,� ft <br /> �1 <br />