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1997-008927 - new septic
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2695 Countryside Drive West - 04-117-23-13-0005
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1997-008927 - new septic
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Last modified
8/22/2023 5:07:33 PM
Creation date
5/3/2016 12:40:35 PM
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Template:
x Address Old
House Number
2695
Street Name
Countryside
Street Type
Drive
Street Direction
West
Address
2695 Countryside Dr W
Document Type
Permits/Inspections
PIN
0411723130005
Supplemental fields
ProcessedPID
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, MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> � �,I�' <br /> A. FLOW Lstimated Scwaec Flows in Galluns per day � <br /> Estimated 9 o a gpd (see pages D-7 or I-3, 4, 5) �g�� <br /> um bcr <br /> or measured - gpd x 1.5 = - ��°�ms Type I Typc:fi Ty�III �� <br /> z soo zu i so <br /> B. SEPTIC TANK LIQUID VOLUMES 3 aso 30o Z�a o� <br /> 4 600 375 2�h ���� <br /> /- la s'v �- I-�o�� ��:llons (see pages C-3 or C-5) s �so aso ��,., ,o <br /> - 6 900 525 332 T�x t, <br /> 7 1050 600 370 m <br /> 8 1200 675 408 �dW„d <br /> C. SOILS (refer to site evaluation) <br /> �� % Sl` IKTYbIIC'� iti�.•�in Il��m <br /> 1. Depth to restricting layer = ��► -�.y � 3� ' inches ��r����f V�linunumLi,u�d �.� K�" , u, <br /> 2. Depth of percolation tests = 1 a" inches Na�,�yv x«`b�.�`�;:'P�=:� <br /> 11«lrcwms C� <br /> 3. Percolation rate )I, I mpi z a ks� ,�o "u <br /> 3 0.a �oc� �soo <br /> 4. Land slope '�- % ,�9 '� ;� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = �, ' <br /> �l D O gpd x 0.83 sq. ft./gpd = �2 sq. ft.-r�n�v= ga � <br /> 2. Select width of rock layer (10 feet or less) = 1 � ft. <br /> 3. Length of rock layer = Area+ Width = <br /> �6�_sq. ft. 1 /o ft. _ �� ft. Rock Bed <br /> tif•f•f•f•f•f•r•r���f�f�f�f�r�r T <br /> ....ti.�.�.�.�.�.. . .. . �.ti.... <br /> f•r.f•f.r.l�l.t:l�f•l•f•f•t•: <br /> ti•ti•ti•ti•ti•ti•ti•ti••.•ti•ti•ti•ti•ti•ti• Width 5]0 ft. <br /> •r•r•r•r•r•r•r.r•r•r•r•r�f•r•r <br /> . ti••,•ti•ti.ti•ti.ti••,••,.•,.•,.•,.•,.•,. <br /> �•r•:•:•:.r•:•r•:•r•:•:•:•:•: <br /> E. ROCK VOLUME �-- Length --� <br /> 1. Mulriply rock area by rock depth to get cubic feet of rock; <br /> 4�a 1 sq. ft. x ,c� ft. _ � cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. + 27 = ��cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> _� cu. yd. x 1.4 ton/cu. yd. = y s� tons. <br /> F. ADSORPTION WIDTH L�A-K �--o� ►� <br /> 1. Percolation rate in top 12 inches of soil is � , I mpi Absorption Width Sizing 7'ablc <br /> Percoladon Rate Callons Ratio of <br /> 2. Select allowable soil loading rate from table on page E-; in Minutesper Soil Tezture �xr day per Absorpiion wid�h <br /> / fnch(MPl) squnre foot to Rock Layer <br /> ,�-I S gpd/f t2 w�d�n <br /> 3. Calcu:ate adsorption width ratio by dividing rock layer Fae�er than 0.l• c�u sa� .---- �..-. <br /> 0.1 b S Send 1.20 1.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.��o s•• Fine Sand" o.�o z.00 <br /> 6 to IS Sandy Lcum 0.79 1.52 <br /> 1.20 gpd/ft�+ ,►�.� gpd/ft2= � �(. � I6 to 30 �am o.�o z.��, <br /> 31 to 45 Silt l.oam 0:� 2.40 <br /> Cheek this value on page E-16. �,�;'0 e'"�n' "' �4 � S.11O <br /> 4. Multiply adsorption width ratio by rock layer width to get SIoZ���an c�sy _____ ._.__ <br /> required adsorption width; <br /> 2.�� x�_ft =�,� ft <br /> 1 <br /> / <br /> 1 <br />
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