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� MOUND DESIGN WORKSHEET <br /> �� �os (For sows up to 1200 gpd) <br /> A. �.�w Estimued Se�vabe Flo�in Gallo�s per D�y(gp� I <br /> Estimated b0 gpd <br /> N�anbcr <br /> � - - ot 7ype 1 �ryp��t lype�t� I �pe rv <br /> or measured x 1.5 = gpdo a�►��„� <br /> 2 30o zis iso � <br /> � 3 �so �oo zis .� <br /> B. SF�'TIC TANK LIQUID VOLUMES 4 6°° "s zs� ,� <br /> s �so �so �s• <br /> � �)].SO �9 1-/OO c7 g�0I1S 6 9�0 5?S 372 � <br /> 7 1�50 600 370 m,� <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) �s� �4'' N,�� �-- ►*-- <br /> 1. Depth to restricting layer = �,o,��a�" inches �N»a'`- B °� �',,� �,� <br /> 2. Depth of percolation tests = inches `''"`' `""`' <br /> 3. Percolation nte 11 . 1 mpi �i«�i` �'.oSOoo i'.'s o <br /> 4. I.aztd slope �-1 % s«6 i.soo uso <br /> �a a �,000 �.000 <br /> we 9 Ses h�.C-6 (t 1S) <br /> D. ROCK LAYER DIlvv�NSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> �oo . gpd x 0.83 sq. ft./gpd = �� sq. ft.+����=���� <br /> 2. Select width of rock layer (10 feet or less) _ >o ft. <br /> 3. Length of rock layer = area+width = R� g� <br /> ��•Sq. 1 l. "'�' /(� 1�. =� 1 C. 1 f1`1�1���'►�����1 fti�ti fti f1 fti f\�1 f1 <br /> �� <br /> 1.1•ti•\•\•\•�•�•ti•�.ti•ti•ti•ti•ti.�•ti <br /> {?ti�{!{:�f�:��{r��ti�tirti�tiftif�r�fti idth 510 ft. <br /> r•r•r•f•r•r•�•r�r•r•r•�•�•f•r•r• <br /> �.ti.�.�•�•ti•ti•ti•ti•�•�•�.�•�•�•�•� <br /> .r.�.r.r.f.f.f.r.r r.r.�.r.r.r.f. <br /> E. ROCK VOLUME �- �'g�' -� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> ss�sq. ft. x .L��ft. _�s�, cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��,cu.ft. -�-27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd.x 1.4 ton/cu. yd. _ � tons. <br /> F. ADSORI''TION WIDTH GLI� LU A n�� „s, �,y,,��,s,�„ Lbk <br /> 1. Percolation rate in top 12 inches of soil is )�. � mpi r�,�,,,tl�,�,,, �� A.�.d <br /> M�m,u�pR�►, Soil Texture M.� 'a� <br /> ��� Ir �►.ar�a <br /> da <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.20 l.00 <br /> � 0.1 to 5 Sand ]•20 1.00 <br /> ��_ gpd/ft� 0.1 to 5 Fine Sand� 0.6� 2.00 <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16�o�o t,o�, o.bo 2.00 <br /> � }� $ }' 31 to 45 Silt Loam OSO 2.40 <br /> load.ing rate of 1.20 gpd/ft2 by allowable soil loading rate; ��o bo ciay�,o�, o.a5 2.6� <br /> 61 t0 120 Clay 024 �.00 <br /> 1.20 �C�/ft2y����gpd/ft� = a.l.� Slower than 120 Cla - - <br /> ^Soil luvin6 504 or more d hne w vcy fv,e�u,d <br /> 4. Multiply adsorption width ratio by rock layer width to get , <br /> required adsorption width; ' <br /> �.�'�x�o ft =�2ft � <br />