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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Gstimaicd Scwagc Flows in Galluns pa day <br /> Estimated �1 <<� gpd (see pages D-7 or I-3,4, 5) n�m�� �s`�� � <br /> of 7'ypc 1 Typc ll Typc Ilf Typc � <br /> or measured -- gpd x 1.5 = -- ,����„R,5 �v <br /> 2 3(b 225 180 <br /> B. SEPTIC TANK LIQUID VOLLTMES 3 aso 30o Z�a o� <br /> q 600 3�5 2S6 ���� <br /> 1 -1 a ��� �t 1-10o C gallons (see pagC� C-3 or C-.5) s ,so aso z�a ;, <br /> 6 900 525 332 '��• <br /> 7 ]O50 600 370 m <br /> 8 1200 675 408 �d„md <br /> C. SOILS (refer to site evaluation) , <br /> I! Scplic Tsok Gpxili.�y,in gyllous <br /> 1. Depth to restricting layer = 22-t u 3 v inches _ <br /> �� Vwnbcr o( \linimum I.�quid Liquid c.pr.�uy with <br /> 2. Depth of percolation tests = �a lllCtl�S �w���■ c�.a�y �ub.rcdi.�wc.l <br /> 3. Percolation rate 4�� � mpi 2w ks� �� ��u <br /> 7 of 4 �(X7D 15W <br /> 4 or 6 ISc10 2250 <br /> 4. Land slope % �.a a 9 xa,o woo <br /> over 9 ----- <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = , <br /> 7 v gpd x 0.83 sq. ft./gpd = a� sq. ft-�►o�� ��y`' <br /> 2. Select width of rock layer (10 feet or less) _ /v ft. <br /> 3. Length of rock layer = Area -:- Width = <br /> ,�_sq. f t. y �f t. _ !��! f t. Rock Bed <br /> r•t•f•r•f.r•r•�•l•t•��l•f•f�l <br /> ti,.,,..,ti,ti,ti,ti,ti,. . .� ti,�,ti,ti, <br /> .f.f.;./.f.f.f.f:f:f.J.f.f.j.f <br /> . ti•ti•ti•ti•ti•1•ti•ti•ti•ti•ti•ti•ti•ti• idth SlOft. <br /> . . , .f.l.l•t•l.t•f•l•�•f•t•t•t•f•l <br /> � •..�.�.� �.� ... .. .........�. 1 <br /> E. ROCK VOLUME �� : f.::f.f.:.:.:.f <br /> Length -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> {�y. sq. ft. x .�.ft. _ �cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �► cu. ft. + 27 = a�_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �� cu. yd. x 1.4 ton/cu. yd. _ � tons. <br /> F. ADSORPTION WIDTH LLA�-( Lo A v►-� <br /> Absorplion W(Jth Slzlnr Table <br /> 1. Percolation rate in top 12 inches of soil is u. I mpi <br /> I'ucolation Re� G�Ilons Rstio of <br /> 2. Select allowable soil loading rate from table on page E-; in Minutctpu Soil Texturc ��a�y�� ,,��«�W���h <br /> Inch(MPI) sqwre foot �o Rock l�ycr <br /> �� gPd�f� w�a�n <br /> 3. Calculate adsorption width ratio by dividing rock Iayer Fa��erthan0.1• c�sy,a ----- ---- <br /> o.i w s s.�d i.zo i.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.�a s•• ��„�s�,a•• o.�o z.�o <br /> 1.20 d/ft2 . �� d/ft — a,1�7 6�o�s s,�,ay� 0.�9 i.sz <br /> �. Z 1610 30 Loam 0.60 2.00 <br /> 8P gP — ,��0 45 s�i�t.�,� o.so Z.ao <br /> Check this value on page E-16. ��o Clny Lo�n. � 2.�� <br /> 60 to 1271 ay 4 S.W <br /> 4. Multiply adsorption width ratio by rock layer width to get s����n���, Clay --- --- <br /> .. <br /> required adsorption width; <br /> � � a.�'1 x�ft =�Zft <br /> _J <br />