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. � 1��TM�' SELECTION PROC�DURE <br /> � �. Dete�ine pu�p capacity: <br /> . A• ��a�i�y distribution <br /> _ 1• Minimum required discharge is 10 gpm <br /> 2. Maximum suggested discharge is 45 gpm. For other <br /> establishments at least 10%greater than the water supply rate, <br /> but no faster than the rate at which effluent will flow out of the <br /> distribution device. <br /> B. Pressure distributaon <br /> See pressure distribution work sheet <br /> Fro�n A or B Sel�cted pump capacity: �,�r gp� <br /> 2. I�etern��ne pump head requirements: <br /> A. Elevation difference between pump and point of discharge? soil treatment system <br /> �� feet &point of discharge <br /> o�.Yap o!;. I I'Z- <br /> B.Special head requirement? (See Figure at right- Special Head Requirements) total pipe <br /> �� feet length <br /> inlet �" ��elevation <br /> C. Calculate Friction loss pipe difference <br /> � ------- -- - <br /> 1. Select pipe diameter_�_� ;_;_..__...._.__... <br /> .. <br /> : ,=---------------------------- •---� L <br /> 2. Enter Figure E-9 with gpm (lA or B) and pipe diameter(Cl). <br /> Read friction loss in feet per 100 feet from Fig-ure E-9 Special Head Requirements <br /> Friction Loss = a,�_ft/100ft of pipe Gravity Distribution 0 ft <br /> 3. Deternune total pipe length hom pump discharge to soil treatment Pressure Distribution 5 ft <br /> discharge point. Estimate by adding 25 percent to pipe length for <br /> fitting loss. Total pipe length times 1.25 = equivalent pipe length <br /> '� �� feet x 1.25 = � O feet E-9: Friction Loss in Plastic Pipe <br /> 4. Calculate total friction loss by multiplying friction loss (C2) Per 100 feet <br /> in ft/100 ft by the equivalent pipe length (C3) and divide b 100. nominal <br /> y pipe diameter <br /> _ ���� �.� ft/100ft x ��J �100 -_ �'7 ft (low rate 1.5" 2° 3° <br /> -----_ - pm <br /> � D. Total head required is the sum of elevation difference (A),special 20 2.47 OJ3 0.11 <br /> head requirements (B), and total friction loss (C4) 25 3.73 1.11 O.16 <br /> �� <br /> ft+ 5� ft+ �_�_ft = 30 5.23 1.55 0.23 <br /> Z'ptdl ]-�eaC�: '� f QQt 35 6.96 2,Ob 0,30 <br /> 40 8;91 2,64 0,39 <br /> 3. ��ygg� ������1��� 45 11.07 3.28 0.48 <br /> 50 13.46 3.99 0.58 <br /> A pump must be selected to deliver at least v`�'_gpm 55 4,76 0,70 <br /> (1A or B)with at least ��>T feet of total head (2D) 60 5.60 0,82 <br /> 65 6.48 0.95 <br /> _ 70 7.44 1.09 <br /> I�reby certi�ha±I�ve cor�pleted this work in accordance with applicable ordinances, rules and laws. <br /> ���-� ��G J. �� �_.�.�..___ �signature) � license# � - p --� �,,,. <br /> t ) J ) (�ate) <br />