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1996-008390 - new septic system
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2755 Copper View Drive - 33-118-23-43-0019
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1996-008390 - new septic system
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Last modified
8/22/2023 4:52:15 PM
Creation date
4/28/2016 4:04:43 PM
Metadata
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Template:
x Address Old
House Number
2755
Street Name
Copper View
Street Type
Drive
Address
2755 Copper View Drive
Document Type
Septic
PIN
3311823430019
Supplemental fields
ProcessedPID
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, , MOUND DESIGN WORKSHEET <br /> ' ' ' ' (For Flows up to 1200 gpd) <br /> a. �,�w Estimued Sew�ge F7ow in Gallons per Day(gpd) ..� <br /> Estimated. �' ;C gpd H�� <br /> or measured -- x 1.5 = - gpd. a��� Ty�`I �'p`ic �rya nl �ry�rv <br /> z soo zu �so 6oa. <br /> 3 450 300 218 °r <br /> B. SII'TTC TANK LIQUID VOLUMES � a 60o s�s u6 .� <br /> _ s �so aso zga �, <br /> � - ) � _ = ,-/�� :, J gdllOI1S 6 900 525 332 '� <br /> 7 IQ50 600 370 odir <br /> �.m„ <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) N�� <br /> �.� ��'' <br /> 1. Depth to restricting layer = i'-,o' �o .�'-a'' inches a�� � � <br /> 2. Depth of percolation tests = 1 � inches <br /> 3. Percolation rate .C.�; mpi 23 a� ,'000 ;•.s o <br /> 4. Land slope S % ;a 8 �.o�o0 3.0 0 <br /> mer 9 See fig.C-6 (x IS) <br /> D. ROCK LAYER DII�ZII�ISIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = � <br /> �<<� . gpd x 0.83 sq. ft./gpd = (��{� sq. ft.-t�o�o=(o��" <br /> 2 Select width of rock layer (10 feet or less) _ /o ft. <br /> 3. Length of rock layer = area=width = Rock Bed <br /> �.��� sq. ft. 1 �o ft. = t.-�! ft. �.�.,.,.�.ti.,.�.ti.,.�.ti.ti.�.ti.�., <br /> r.r•f•�•r•r•r•f•r•r•r•f•r•f•r•r• <br /> 1.�•�•1•ti.ti•ti•ti•ti•�•ti•�•ti•ti•L•L•ti <br /> tir{f{:{f�ftif{jtiftif{f{:{r{f{{{ftifti �dth <_10 ft. <br /> . +f�.�-�f�f`-�ryf�f�r�f�f�f1f�j1�� <br /> .f.f.f.r.f.f•f•/.f.�.t.f.f.f.f.J. . <br /> E. ROCK VOLLJME �- �'g�' -� � <br /> , <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; - <br /> '=�U sq. ft. x �.,, � ft. _ �i cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��� cu. ft. -27= �� cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �� cu. yd. x 1.4 ton/cu. yd. _ ;�� tons. <br /> F. ADSORPTZON WIDTH L'-�'�' '_°'� '`l ,� b«,w,a�,s�, �bi� <br /> 1. Percolation rate in top 12 inches of soil is �.c mpi P�o,,h�,�,� ��,. a.�d <br /> Mii,ucea per ur_}, Soil Textum �,q,�,R �,d,`d <br /> (mpil I.e •E.Qvem <br /> deA <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 12o i.00 <br /> � 0.1 to� Sand 120 1.00 <br /> .'� � �Jd�ffi 0.1 to� FineSand" �•� Z•� <br /> 6 to 15 ndy Loam 0.79 1 S2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16�o�o t�a� o.bo 2.00 <br /> � �' g }' 31 to 45 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo c�a Loan, o.4s 2.6� <br /> 1.20 d tt2i L ' d/ft� _ � . U� 61 co 120 �iay oz4 �_oo <br /> $P / , 1 s gP Slower than 120 Cla <br /> "Soil}uving 509G or mae d fine or very fine sand <br /> 4. Multiply adsorption width ratio by rock layer tvidth to get <br /> required adsorption width; <br /> ���� x�_ft =��s.� ft � l <br /> �J <br />
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