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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. �QW Estimued Seavage Flow in Galloos pa Day(gpd) .:� <br /> FSt1II13tfC� � v �JC� N�ba ,ry�I ,�lI 7ype III Type IV <br /> or measured x 1.5 = " gpd. s�a►�� <br /> 2 soo Zu �so 6oa, <br /> 3 450 300 2]8 °r <br /> B. SEPTTC TANK LIQUID VOLUMES 4 �o0 3�s u� .�. <br /> s �so aso �sa � <br /> �_��,�J `�: I-1 Go�� gallons i t� � 3�0 �,�,. <br /> ��-,-f,�-�,, ,, s t2oo 6�s aoa <br /> C. SOILS (refer to site evaluation) ''�''`�'�� � �o <br /> N�c� ,.�,� ,�m <br /> �� of s�..� ��, <br /> 1. Depth to restricting layer = ]i�,",, i s��3o inches U� �� &a� �, �,, <br /> 2 Depth of percolation tests = 1 � inches `'"m`' `""m`' <br /> 3. Percolation rate I), mpi 23a'a ,'o�o°o ;•.s o <br /> 5 or 6 1 S00 2,250 <br /> 4. Land slope �j `70 ,a s z000 3.000 <br /> wa 9 Sce fig.C-6 (z IS) <br /> D. ROCK LAYER DIlviIIVSIONS <br /> 1. Multiply flow rate by 0.83 to obta.in required area of rock <br /> layer: A x 0.83 = <br /> �.�v gpd x 0.83 sq. ft./gpd = a-� sq. ft.�-»�v=��yD <br /> 2 Select width of rock layer(10 feet or less) _ ,�ft. <br /> 3. Length of rock layer = area=width = Rock Bed <br /> i��U sq. ft.= l!� ft. = i.,s1 ft. �.ti.�.,...ti.�.�.ti.ti.�.ti.ti.....�.� <br /> �•r•f•�•1•f•I•/•r•f•t•t•f•f•l•r• <br /> 't.ti•ti•ti•�•ti•ti•ti•ti•ti.ti.ti•ti•ti.�.ti.1 <br /> tifti:ti:ti�tifti:�:tifti:ti�ti�Lftftiftifti�ti idth 510 ft. <br /> . 1fti���tifti�ti�ti�,tiftiftifti�tiftil�rL�tif1 <br /> .f.r.f.l.f.f.f.f.f.f.r.t.j.f.f.j. <br /> E. ROCK VOLUME �— �ng�' —� ` ' <br /> i <br /> 1_ Multiply rock area by rock depth to get cubic feet of rock; ��� <br /> uy sq. ft. x /.0�ft. _�cu. ft. <br /> 2 Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> L cu. ft. �27= �,'� cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �� cu. yd. x 1.4 ton/cu. yd. = 3� tons. <br /> F. ADSORPT'TON WIDTH �-LA`� `--o'�"-� �, �,w,a�,S�„ Table <br /> 1. Percolation rate in top 12 inches of soil is 11.) mpi P��ieaiRi� ��,. R.�d <br /> Minutesperuich SO117E'Xtllf2 �,y„�� �O�`ad��ie <br /> (mpil r.e .�a, <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.20 l.00 <br /> L'' ; d/f�Z 0.1 to� Sand 1.20 1.00 <br /> ' `� � 0.1 to� Fne Sand" �•b� 2•� <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adsorption width ratio by dividing rock layer 3i to a� si�i t,o m o50 2.� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to�o ciay Loa�, o.a� 2.6� <br /> 61 tU 120 Clay 024 �.00 <br /> 1.20 gPd/ft2� y � gpd/ft�_ �.t�� Slower than 120 Cla -- — <br /> "Soil having�09G or mae o(fu+e or vey fine xnd <br /> 4. Multiply adsorption width ratio by rock layer�vidth to get <br /> required adsorption width; <br /> �.�,� x /� ft=�!�.� ft <br /> .� <br />