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2008-P12100 - new septic system
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2010 Colin Drive - 03-117-23-21-0014
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2008-P12100 - new septic system
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Entry Properties
Last modified
8/22/2023 4:34:12 PM
Creation date
4/20/2016 1:13:08 PM
Metadata
Fields
Template:
x Address Old
House Number
2010
Street Name
Colin
Street Type
Drive
Address
2010 Colin Dr
Document Type
Septic
PIN
0311723210014
Supplemental fields
ProcessedPID
Updated
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, ��'� �?'��' �<,�'�.. �� ��C-�14� <br /> ,,�:.^a.r-., <br /> 1VIO�iJND DESIGN WORI< SHEET (For Flaws u to 1200 d) � <br /> A. Av�:rage Design FLOW A-1: Estimateei Sewage Flows in Gallons per Day <br /> num er of <br /> Estimated �_ gpd (see figure A-1) bedrooms Class I Class II Class III Class IV , <br /> or measured --� x 1.5 (safety factor) _ �-- gpd 2 soo 225 �ao bo% <br /> 3 450 300 218 ofthe <br /> 4 600 375 256 values <br /> B. SEPTIC TAl\TK Capacity 5 750 450 294 in the <br /> 6 900 525 332 Classl, <br /> �v��a�„! F,.�,n-t�- 7 1050 600 370 II, or III <br /> �%�c� c� gallons (see figure C-1) �����,�, g 1200 675 408 columns. <br /> I ac�c?ap�,! °oaAti.L..lrlfkm4o�`ct- �ocati.l�cavg� � - <br /> C. SOILS (refCP t0 SItE eUCIIUQt1011� C-1: Se ticTankCa acities(in ailons <br /> Number of Minimum Liquid Liquid capacity with Liquid capaciry <br /> 1. De th to restrictin la eI" _ � Bedrooms Ca aci arba e dis osal W����sposal& <br /> P g y d��•�?�,�•l�' feet P ry S B P liftinside <br /> 2. Depth of percolation tests = �s � feet zo�ie55 �so 1125 �soo <br /> 3. Texture �c�f�v✓� 3or4 �000 �soo z000 <br /> 5 or6 1500 2250 3000 <br /> Percolationrate 1�.o mpi �,8or9 Z000 3000 <br /> 4. Soil loading rate ,to0 gpd/sqft (see figure D-33) <br /> 5. Percent land slope f� % <br /> D. ItOCK LAYER I3IMENSIOI�TS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rocic layer area. <br /> '�'!�� gpd x 0.83 sqft/gpd = `�?,�a sqft-t�a���!�� <br /> 2. Determine rock layer width = 0.83 sqft/gpd �< linear Loading Rate (�LLI� <br /> 0.83 sqft/gpd x _ � a, gpd/sqft = 1� ft �ound LLf� <br /> 3. Length of rock layer = area = width = <br /> �� sqft (D1) = � u ft (D2) = �� ft < � 20 ��0 < � 2 <br /> E. I�OCK VOLUME > 120 fVl PI < 6 <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> �1 ►� sqft x 1 ft = �t a cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cuUic yards <br /> �� cuft = 27 cuyd/cuft = 1,S' cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> �_ cuyd x 1.4 ton/cuyd = a ) tons <br /> D-33: Absorp[ion Wid[h Sizing Table <br /> �F. SEY�AGE ABSORPTION WII�TH Percola�ion Ra�c Loading Rate <br /> in Minutes per Soil Texture Gallons Absorpiion <br /> Inch per day per Ratio <br /> �"fP� s uare foot <br /> Faster than 5 Coarse Sand L20 1.00 <br /> Rledium Sand <br /> Absorption width equals absorption ratio (See Figure D-33) LoamySend <br /> Fine Sand <br /> times rock layer width (D2) 16 to 30 Loam o.� z.� <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> � <br /> oi.�(,) �( �_ f t = c�,(��(� f t 46 to 60 Sancly Qay Lo 0.45 2.67 <br /> Siliy Clay Loam � <br /> 61 to 120 Silty Clay 0.24 5.00 <br /> Sandy Clay <br /> Cla <br /> Slower lhan]20' <br /> 'Sysiem designed for ihese soils mus�be oWer ar per(ormence <br />
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