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2010-00294 - septic
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650 Big Island - PID: 22-117-23-31-0035/0028
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2010-00294 - septic
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Last modified
8/22/2023 4:12:11 PM
Creation date
4/18/2016 2:04:36 PM
Metadata
Fields
Template:
x Address Old
House Number
650
Street Name
Big Island
Address
650 Big Island
Document Type
Septic
PIN
2211723310035
Supplemental fields
ProcessedPID
Updated
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J����y���,c��1 <br /> � � <br /> lVIOUND DESIGN WORK SHEET (For Flows u to 1200 d) <br /> . A. Avr..rage Design FLOW A-1: Estimated Sewage Flows in Gailons per Day <br /> 1`'`�'`'�`"'�1'"�``� num er o <br /> EstimateCl �(�C:J gPC� (see figure A-1) bedrooms Class I Class 11 Closs III Class IV <br /> or measured �-- x 1.5 (safety factor) - �- gpd 2 soo 225 �80 60% <br /> 3 450 300 218 ofthe <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity 5 750 450 294 in the <br /> 6 900 525 332 Class I, <br /> a,-1��'� gallons (see figure G1) � to5o boo 3�0 ��, or�u <br /> �,���,�.ti�,�.�-:.��,�,� ������.� 8 1200 675 408 columns. <br /> s � �t l�vc���.,,lY�1vt��=- �.�����r�e���-. <br /> C. SOf LS (refer to site evaluation) C-l: 5e lic Tank Ca acilies(in allons <br /> T �, Number of Minimum Liquid Liquid capacity with W���disposal& <br /> 1. Depth to restricting layer = i E�� 1 •�,1,�,I,+�feet Bedrooms Capacity garbage disposal <br /> --r— lifl inside <br /> 2. Depth of percolaHon tests = 1� a feet z o�iess �so uzs �s� <br /> 3. Texture �t�V��� t.�'���.,i 3 0�a �000 isoo 2000 <br /> 5 or 6 1500 2250 3� <br /> Percolation rate 1�. � mpi �,8 or 9 z000 3000 <br /> 4. Soil loading rate � �� gpd/sqft (see figure D-33) <br /> 5. Percent land slope � % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> 4�� gpd x 0.83 sqft/gpd = ��Z. sqft <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd x 1 '� gpd/sqft= 1c1 ft Mound LLR <br /> 3. Length of rock layer = area = width = <br /> :>?,rvz.. sqft (Dl) = �ft (D2) _ ;�; ft < 120 M PI < � 2 <br /> E. ROCK VOLUME > 120 M PI < C� <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> :'�"��-- sqft x 1 ft = :f,:�=� cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> "'�- cuft = 27 cuyd/cuft = �cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> ) �� cuyd x 1.4 ton/cuyd = 1 � tons <br /> D-33: Absorption Width Sizing Table <br /> F. SEWAGE ABSORPTION WIDTH Percolalion Rate Loading Rele <br /> in Minutes per Soil Tezture Gallons Absorption <br /> Inch per day per Ralio <br /> Mp� s uarc(ool <br /> Faster lhan 5 Coarse Sand 1.20 )_pp <br /> � Mcdium Sand <br /> Absorption width equals absorption ratio (See Figure D-33) �amySand <br /> Finc Sand <br /> times rock layer width (D2) 16 to 30 Loa,,, o.� z.� <br /> 31 to 45 Sili Loam 0.50 2.40 <br /> ���� �( f� ft = �.E�. f t 46 to 60 Sandy Clay Lo 0.45 2.67 <br /> Silty Clay Loam <br /> 61 l0 120 Silty Ciay 0.24 5.00 <br /> - Sandy Clay <br /> Cla <br /> Slower than 120' <br /> •sys��m au����a ro�m���;�s�.,,�n�om«or aKo��� <br />
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