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� •��.� P <br /> ���„�,-r `` ' � Job# Egan <br /> Preoosewrw <br /> University of Minnesota Mound Design Worksheet <br /> Greater than 1%Siopes <br /> A FLOW <br /> Estimated (�� �y.,�r TrNG�\ 375 �rd(see flgure A-1) <br /> or measured � <br /> x 1.5(safeiy factor)= 0 �d <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> Septic tank capacity 2000 gallons(see figu�e Gi) <br /> Number of tankslcompartrnents 2 <br /> Effluent Filter (yes/no) no <br /> C-1 Septic Tank Capacity in Gallons <br /> Number of Minimun C�acity with Capacity with <br /> Bectooms Capacity G�b.Disp. Disp.and Lift <br /> 2 or less ,_750 1125 f=`. 9500 : <br /> 3 or 4 t Ofl0 ' ' t5pp 2000 <br /> 5 or 6 1� 2250 3000 <br /> 7,8 a�9 '-�000 ` 300Q d�00 <br /> C. SOILS(Site evaluation dafa) <br /> 1. Depth to restricqng layer= 1.2 feet <br /> 2. Depth of percola6on tests= 12 inches <br /> 3. Texture �� <br /> 4. Soil loading rate(see Figure D-33) 0.60 �d1 ft� <br /> Percolation rate 22 MPI <br /> 5. %Land Slope 21.0 % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock tayer.Item A x 0.83= <br /> 375 �d x 0.83 f1�/c�d= 320 ft2 <br /> 2. Determine rock layer width =0.83 fY`lgpd x Linear Loading Rate(LLR)(see LLR chart) <br /> 0.83 ft�/c,�d x = 8.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <-12 <br /> >=120 MPI <_6 <br /> 3. Lengfh of roctc layer=area divided by width= <br /> 320.0 ft� I 8.0 feet= 40.0 ft <br /> E. ROCK VOLUME <br /> t. Multiply rack area by rock depth to get cubic feet of rocic <br /> 320.0 X 1_0 ft= 320.0 ft3 <br /> 2. Divide ft3 by 27 ft3/yd3 to get cubic yards <br /> 320_0 ft3 / 27 = 11.9 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 11.9 yd3 X 1.4 tordyd3 = 16.6 tons <br /> Page 1 of 6 <br />