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, t . <br /> � <br /> 3. TRENCH OR BED BOTTOM AREA <br /> H. For trenches with 6 inches of rock below the pipe: <br /> A x F= gpd x ft/gpd = ftZ <br /> I. For trenches with 12 inches of rock below the pipe: <br /> A x F x 0.8= 300 gpd x 2 fUgpd x 0.8 = 480.0 ft2 <br /> J. For trenches with 18 inches of rock below the pipe: <br /> A x F x 0.66= gpd x ft/gpd x 0.66= ft2 <br /> K. For trenches with 24 inches of rock below the pipe: <br /> A x F x 0.6= gpd x ft/gpd x 0.6= ft2 <br /> L. For gravity beds with 6 or 12 inches of rock below the pipe; <br /> 1.5xAxF= 1.5x gpdx ft/gpd = ft2 <br /> M. For pressure beds with 6 or 12 inches of rock below the pipe; <br /> A x F= gpd x fUgpd = ft2 <br /> 4. DISTRIBUTION(Check all that apply) <br /> Bed(<6%slope) X Drop Boxes(any slope) Rock <br /> X Trenches Distribution Box(<3%) X Chamber <br /> Pressure X Gravity Gravelless <br /> 5. SYSTEM WIDTH,LENGTH AND VOLUME <br /> M. Select width= 3.0 ft <br /> N. If using rock,divide bottom area by width:(H, I,J or K)divided by P=lineal feet <br /> 480.0 ft/ 3.0 ft = 160.0 lineal feet <br /> Rock depth below distribution pipe plus 0.5 foot times bottom area: <br /> (Rock depth+0.5 foot)x Area H, I,J,K, L) <br /> ( ft+0.5 ft)x 0 ft2 = ft3 <br /> Volume in cubic yards=volume in cubic feet divided by 27 <br /> I 27= yd3 <br /> Weight of rock in tons=cubic yards times 1.4 <br /> x 1.4= tons <br /> 0. If using 10"Gravelless Pipe, length=Flow(A)x Gravelless SSF(see figure D-9) <br /> gpd x � fUgpd = lineal feet <br /> P. If using a Chamber(H, I,J, K(based on height of chamber slats)divided by width of chamber in ft) <br /> 480.0 ft2 I 3.0 ft = 160.0 lineal feet <br /> Page 2 of 2 <br /> i <br /> i <br />