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2003-P06752 - new septic system
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4355 Chippewa Lane - 31-118-23-42-0020
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2003-P06752 - new septic system
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Last modified
8/22/2023 4:32:33 PM
Creation date
4/14/2016 12:58:48 PM
Metadata
Fields
Template:
x Address Old
House Number
4355
Street Name
Chippewa
Street Type
Lane
Address
4355 Chippewa Lane
Document Type
Septic
PIN
3111823420020
Supplemental fields
ProcessedPID
Updated
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� , , <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW a,�.�e s.�.Fl�u+cnu«�ar d <br /> Fstimated�gpd �d, c a'°a n'p°' �°° �`yp`m ,�' <br /> or measured_.:_x 1.5 =.=._ <br /> LI UID VOLUMES 4 � � �� � <br /> B. SEP'I'IC TA.NK Q a y� s�s m �y"p� <br /> a - !o0 o gallons . � �oso eoo r�o 11�a <br /> . I 1 i t200 673 � Q1 <br /> C. SOILS (refer to site evaluation) <br /> L� �� �� A� <br /> 1. Depth to restricting layer� � � ��- �lnches feet �M �� �,� ,�,�, <br /> 2. Depth of percolation tests= �.=inches �"' `�' p"'""'"' """"° <br /> / 3wlr Tf0 112! 1� <br /> 3. Textwre ��-�� ��� Percolation rate �•S mpi �.• �� �� � <br /> 4. Land slope �� % ''""• '°° °° � <br /> � <br /> D. R K LA ,D I <br /> 1, Multiply flow rate by 0.83 to obtain required area of rock layer. A x 0.83 = <br /> �_,o_gpd x 0.83 sq. ft./gpd = �� K sq. h.�,���5�►�� <br /> 2 Select width of rocic layer (max 1�0' if<120 mpi max 5') = i=ft. <br /> 3. Length of rock layer= azea+width= �- » w . . <br /> � . �,�, �, <br /> � ��sq. ft + =ft• =�„_ft• �. �, ,� .b 7: <br /> , <br /> �dth �o ft . ' <br /> � <120mpi <10' un� s s ft <br /> >120mpi c5' <br /> E. ROQC VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �i sq. h. x �v S' <br /> k. = s� cu. ft. <br /> 2, Divide cu. ft. by 27 cu. ft/ru. yd. to get cubic yards; <br /> �y.,cu. ft. +27 =�_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�L cu. yd. x 1.4 <br /> ton/cu. yd. _ �tons. <br /> F. ABSORPTION WIDTH A,Dsotptloo H'ldts Slsin;T1DIa <br /> 1. Percolation rate in top 12 inches of soil is �-s� mpi r.�.�.i�.�.m au� ��� <br /> Texture <br /> L_��-�{ t_u✓�v✓1 Mi��r�ea� seu Taan ��r ura w� <br /> �..�er m..o,� co.r�.a.ea �So �.00 <br /> Q 1 p 3 Saed 1.20 I.00 <br /> .2. Select allowable soil loadin rate fzom table; a�a s �a�e o.�o �oo <br /> 8 e p is s.ver�,o.�. a�9 i.s: <br /> • � �a/� ��oa m �a'�.r`'e.�' o' s o0 <br /> 3. Calculate adsorption width ratio by dividing rock layer �'°"'"1°ii120 `�'' 0�0 `.0° <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft�+ . s' gpd/#�_ • �-`'� . <br /> 4. • Multiply adsorption width rdtlo by rock layer width to get <br /> required adsorptlon width; <br /> �x—�= a�°-� � <br />
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