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2003-P06942 - septic
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2003-P06942 - septic
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Entry Properties
Last modified
8/22/2023 5:24:57 PM
Creation date
4/1/2016 2:51:04 PM
Metadata
Fields
Template:
x Address Old
House Number
4775
Street Name
Bayside
Street Type
Road
Address
4775 Bayside Rd
Document Type
Septic
PIN
0611723220019
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. �QW Estimued Sewage Flow in Gallons per Day(gpd) <br /> Estimated � v d N�� � <br /> �-SP or �Y�► �=.:. <br /> or measured - x 1.5 = -- gpd. B��t,,, 7Ya�II TYP�fIf Ty�rv <br /> 2 soo zu �so � <br /> 3 450 300 218 °t <br /> B. SEPTTC TANK LIQiTID VOLUMES 4 �ao 3�s �.s� .� <br /> s �so 4so Z�a m <br /> � a-���� g�o� 6 � su 332 � <br /> � iaso soo s�o ''"' <br /> �.m,. <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) N„m� <br /> �°�:� �"" <br /> 1. Depth to restricting layer = �.�''- 3�, �� inches B�� �,,, �, <br /> 2. Depth of percolation tests = �Z'' inches `�'�'' `""m'' <br /> 3. Percolation rate I o�(� mpi z a� 7so �.�u <br /> 3 or 4 1,000 1,500 <br /> 4. Land slope � % ;a s zoo 0000 <br /> ova 9 See fig.C-6 (x 1S) <br /> D. ROCK LAYER DIIv�TSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = , <br /> y,�o gpd x 0.83 sq. ft./gpd =�2.�sq. ft.+�o"� �i �o° <br /> 2. Select width of rock layer (10 feet or less) _ �o ft. <br /> 3. Length of rock layer = area-�-width = Rock Bed <br /> ��sq. ft. -:- �_ft. _�L ft. �...ti.,.�.ti., �.�.ti.ti.�.,.�.... ti <br /> r.r•r•f•�•r•'r•�•r•f•t•r•r•1'•1•�• <br /> ti.�•�•ti•ti•ti.ti•ti•1.ti•1•ti•ti•ti.ti•ti.t <br /> r.r.f•f•r•r.r.f•r r•f•f•r•r.r•r• idth <_10 ft. <br /> ti.'L.'L.ti.ti•ti•�•ti•ti•ti.\•1.ti•ti•ti•ti•ti <br /> tiftifl�tiftiftiftirtif�ft`�r�f�ftiftifti�ti <br /> ,f./.f.f.r.f.f.l.t.f.f.t.l.l.j.f. <br /> E. ROCK VOLUME �-- �ength -� ,� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �`�� <br /> �--1/� sq. ft. x .� � ft. _ �-�3Qcu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 3o cu. ft. y 27=��cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _ �a tons. <br /> F. ADSORP'ITON WIDTH c,LA-'� 1���-wl n� a,w,a�,s;�, Lbk <br /> 1. Percolation rate in top 12 inches of soil is io,c� mpi r�,,,e�,R,� �,; ;�„ <br /> 1�t�,uer,pR�►, Soil Texture �p�� d�I1b <br /> (mpJ t"" 'r.�� <br /> 2 Select allowable soil loading rate from table; Faster than 0.1 oar�sana 12o i.00 <br /> d/ft� 0.1 to� Sand 120 1.00 <br /> • �S � 0.1 to,i FineSand" �-� 2•� <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adso tion width ratio b dividin rock la er tb co so t,o�, o�� Z� <br /> rp y g Y 31 to 45 s►�c i.�m o� 2-� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ��o bo ctay 1..0�, 0.4� Z6� <br /> 61 t4120 Clay 024 �.00 <br /> 1.20 gpd/ft2y ,�s gpd/ft� = a�lo� slowerthanl2o Ciav - - <br /> "Soil}uving�05C ar morc af fux or vey fux rard <br /> 4. Multiply adsorption width ratio by rock layer�vidth to get <br /> required adsorption width; <br /> ��x��.ft =�_ ft �' <br /> � <br />
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