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2000-P03078 - septic
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4755 Bayside Road - 06-117-23-22-0021
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2000-P03078 - septic
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Last modified
8/22/2023 5:24:59 PM
Creation date
4/1/2016 2:44:53 PM
Metadata
Fields
Template:
x Address Old
House Number
4755
Street Name
Bayside
Street Type
Road
Address
4755 Bayside Rd
Document Type
Septic
PIN
0611723220021
Supplemental fields
ProcessedPID
Updated
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� ` � MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> A. �,�w Estimued Sea�age Flow m Gallons pa Day(gpd) <br /> Estimated '�gPd N�� � <br /> or measured — x 1.5 = — gpd. a��� �`I �'P`n ry��u ry�rv v <br /> 2 300 225 180 sas <br /> 3 450 300 218 •� <br /> B. SII'TTC TANK LIQUID VOLUMES 4 �o0 3�s u� .�. <br /> 5 750 450 Z94 m <br /> j-I;SO a- )��p�c� g3llOI15 7 1050 600 370 od" <br /> ��� <br /> ���,�� 8 12D0 675 408 <br /> C. SOIIS (refer to site evaluation) 34�, ,���, �.�" ��� ,,� ,,� <br /> ct �T� c�,-�, <br /> 1. Depth to restricting layer = i�a�� a�,' a o" inches �� �,, �, <br /> 2 Depth of percolation tests = � a inches `'""' `'"�`' <br /> 3. Percolation rate 3�4 mpi 23«� �'.oso°o i'.'s o <br /> 4. Land slope � �o �t� . �'a <������ �a� ;a a zo�0°o0 000° <br /> wc 9 See fig.C-6 (x 1.� <br /> D. ROCK LAYER DIlv�1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> �Sv gpd x 0.83 sq. ft./gpd = �a� sq. ft.-����o=�`�y° <br /> 2 Select width of rock layer (10 feet or less) = i� ft. <br /> 3. Length of rock layer = area=width= Rock Bed <br /> ��s y sq. ft.i �_ft. _ (.� ft. ..,.�...�.�.,.ti.�.ti.�.,.�.�.�.ti.� <br /> f•r�f•t•�•1•f•t•t•l•t•I•r•f•!•r• <br /> ♦•1•\.�•1•ti•�•ti•ti•ti.ti•ti•1•�•ti•ti•ti <br /> f•r•!•/•r•t•r•Hl•t•t•r•r•l•�•r• <br /> �•ti•�•ti•ti•ti.�.�•ti•ti.ti.�.ti.ti.ti.ti.ti idth S10 t. <br /> ti�tirti�tif~�1rtf�fti��ftirlf��tif1?tfti <br /> .r.�.f.f.�.r.f.f.f.f.r.f.j.�.f.f• _ <br /> E. ROCK VOLUME ~— �'� � �� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> c��y sq. ft. x �.�ft. _ ��� cu. ft. <br /> 2 Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��cu. ft. -27= -�� cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a�cu. yd. x 1.4 ton/cu. yd. _� tons. <br /> F. ADSORP'ITON WIDTH L`-�'� �-o�`'''� ,��,w,��,s�, �� <br /> 1. Percolation rate in top 12 inches of soil is 3,�I mpi p��,��,�,� ;�,;, ,��, <br /> �,�,k, �, Soil Texture ,,e,q„-� �,,,- <br /> t�,� f.� �v <br /> 2 Select allowable soil loading rate from table; Faster than 0.1 oa�sand 1�o l.00 <br /> ���� d/ft� o.i to s sana i2o l.00 <br /> � 0.1 to� Fne Sand" �� 2•� <br /> 6 to 1� ndy Loam 0.79 1�2 <br /> 3. Calculate adso rion width ratio b dividin rock la er 16 to�o �o� o.bo 200 <br /> � }' g }' 31 to 4� Silt Loam �-'� 2•`� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to�o clay Loa� 0.4� 2.6� <br /> 61 t0120 Clay 024 �.00 <br /> 1.20 gpd/ft2i��gpd/ft�= a.C�� Slower than 120 Clav - - <br /> "So;l kuving�OsG or mae d fine ar.Qy Fu+e sutd <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �.�� x lo ft=���� ft <br />
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