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� � MOUND DESIGN WORKSHEET <br /> (For Flo�vs up to 1200 gpd) <br /> A. �,Qw Estimatcd Sew�ge F1ow in Gallons per Day(gpd) <br /> Estimated 7S0 gpd N�,b« � <br /> or measured — x 1.5 = -- gpd. s��� TYP�I �y�u ry�►ir �rv <br /> 2 300 225 180 bas <br /> 3 450 300 218 i4 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 �o0 3�s u� ,�,�, <br /> s �so aso 29a m <br /> I-)aS� �- �-1��� gallons � i� � 3io �� <br /> m�� <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) � �,�� ,,� �� <br /> 1. Depth to restricting layer = �y � I K inches B�� �, �, <br /> 2. Depth of percolation tests = 1 � inches `'"m'' `p"m'' <br /> z a� �so i.i�s <br /> 3. Percolation rate S• 3 mpi 3 a 4 ,.� ,� <br /> 4. Land slope S % ;a g z� �° <br /> wa 9 Sce fig.C-6 (z 1S) <br /> D. ROCK LAYER DINiEIVSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> � S� gpd x 0.83 sq. ft./gpd = �aa sq. ft.�-��J��'�°I <br /> 2. Select width of rock layer (10 feet or less) = io ft. <br /> 3. Length of rock layer = area=width = Rock Bed <br /> i�u�l sq. ft. -�- �o ft. _ �� ft. �.,.�.~...ti.ti.�.�.�.�.�.,.,.�.ti.ti <br /> J•t•t•!•1•1•l•f•f•f•I•r•t•f.f.r• <br /> ti•ti.ti.�•1•\.ti•ti.ti.�.t.ti•ti•ti•ti•ti•ti <br /> tirtifti:ti:tiftiftif�:ti:tirti��ftirti�fti ti idth 510 ft. <br /> r•r•t•r•f•r•r•r•r•r•r•r•r•f•1•!• <br /> 1•ti•ti•ti•ti•ti•t•t•ti•1•ti•L�ti•ti•ti•�•ti <br /> .l.l.f.f.f.r.f.f.f.f.r.f.l.f.f.f. <br /> E. -ROCK VOLUME � �'g�' —� � <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> ��sq. ft. x l.c�S ft. _� cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��t� cu. ft. =27=�_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> :�� cu. yd. x 1.4 ton/cu. yd. _�K tons. <br /> F. ADSORPTTON WIDTH L�-� L`''�''`'1 <br /> Abso on Width Si�n Table <br /> 1. Percolation rate in top 12 inches of soil is S•3 mpi P��,,h�,R,� �Q- �� <br /> �t�,,,4,p�;�, SoilTexture �,� �,"`e <br /> cmpil t.a .b.�.poa, <br /> 2. Select allowable soil loading rate from table; Faster than Q.1 oarse Sand l�o l.00 <br /> •� gpd/ft� 0.1 to� Sand 1.20 1.00 <br /> 0.1 to� Fine Sand" �•� 2-� <br /> 6 to 1� ndy L.oam 0.79 1S2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 co 30 [,o� o.bo 2.00 <br /> � }r g }' 31 to 4� Silt Loam 0-� 2•� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to�o cla �.oa�, o.a� 2_6� <br /> 1.20 gpd/tt2= .�-� gpd/ft�_ �. � 61 co 120 �iay o24 s_oo <br /> 7 Slower than 120 Clav <br /> "Soil having�QSG a mar af fine or vey fine su�d <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> ���'1 x l� ft =�e- ft <br /> � <br />