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2000-P02833 (septic)
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4485 Bayside Road - 06-117-23-21-0003
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2000-P02833 (septic)
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Last modified
8/22/2023 5:24:22 PM
Creation date
4/1/2016 2:32:07 PM
Metadata
Fields
Template:
x Address Old
House Number
4485
Street Name
Bayside
Street Type
Road
Address
4485 Bayside Rd
Document Type
Septic
PIN
0611723210003
Supplemental fields
ProcessedPID
Updated
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� MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW ��a s•wu•��+�a►u���a <br /> e <br /> Fstimated�8Pd _ �d. r+� '�' �•II �m ,�' <br /> or measured=x 1.5 =_._.. <br /> z �oo ns iao � <br /> � �so �ao s�e am <br /> & SFPZTC TANK LIQUID VOLUMES a '9030o si°s m �y�p°e <br /> y�s����� -t^A>���.s -S� sss: ��+���bo,� <br /> I-la�u � I—/ut�0 g�0I13 �Y�w�C� �4\�� i�,Jt,�-� �o�� . � 7 1030 600 770 h�a <br /> . I t I 1200 673 � � <br /> C. SOILS (refer to site evaluation) , <br /> 1. Depth to restricting layer= ►�'',_vnches feet �� <br /> 2. Depth of percolation tests= �a" ��� <br /> � � � �� <br /> 3. Texture ��-�`� ���`'�'� Percolation rate ��� mpi '�`' �� �� ;;� <br /> 4. Land slope �% ,'�"" '°'� '� � <br /> D. R K LA ,D I <br /> 1, Iviultiply flow rate by 0.83 to obtain requi.red area of rock layer. A x 0.83 = , <br /> 2�°_$Pd x 0.83 sq. ft./gpd = ��,�� sq. ft. ��,o�2 ,�,�-�,�,�> �o �,��, <br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') _ _ft. <br /> 3. Length of rock layer area width= � » . .` <br /> � + <br /> • _-a�_,a__sq. ft. + _,Lo_�• = a_' —ft• � �� ~� �-� ' <br /> L � . <br /> Width 1� fc � � � , <br /> � <120mpi <10' �n��---ft <br /> >120mpi <5' �.� ���;n,�,,,�,, , <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by zock depth to get cubic feet of rock;> >�- sq. R x 1,o s <br /> ft. _ �.��-„cu. ft. <br /> 2, Divide cu. ft. by 27 cu. f�/cu. yd. to get cubic yards; <br /> 3a� cu. ft. +27 =.�.,cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; s� cu. yd. x 1.4 <br /> ton/cu.yd. _ .LL,tons. <br /> F. ABSORF''ZTON WIDTH Absorpdoa�'Hidtn Slsi�T1b1• <br /> 1. Percolation rate in top 12 inches o#soil is �mpi �,eo.�.m au� ��� <br /> � ��� MI�per ledi Shc Taan ��r ya w1d�L% <br /> Textvse ��-� __ P� � <br /> Pu�er d�0,I Cor+�Saed I 20 I,00 <br /> 0.1 a 3 S�ed 1.20 1.00 <br /> .2, Select allowable soil loadin rate hom table; a�b s �a s�a o.�o i°° <br /> t� 6 a 1! S�eer Loru 0.79 1.12 <br /> ���� OL'�/�'`- , !1 p43 SIRI.o� 030 240 <br /> �s a ao cz,r�.0.4 a+s �.a� <br /> 3. Calculate adsorption width ratio by dividing rock layer �'°'""�`"120 � °�0 6'0° <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft�+ .`�� gpd/�_ � �� _��%� <br /> 4. � Multiply adsorption.width zatio by rock layer width to get � <br /> required adsoxption width; <br /> � ,���-�x ic�ft= �c�-`i ft <br />
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