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2000-P03179 (new septic)
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2125 Carriage Lane - 10-117-23-24-0037
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2000-P03179 (new septic)
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Entry Properties
Last modified
8/22/2023 3:22:17 PM
Creation date
2/17/2016 11:49:40 AM
Metadata
Fields
Template:
x Address Old
House Number
2125
Street Name
Carriage
Street Type
Lane
Address
2125 Carriage Lane
Document Type
Septic
PIN
1011723240037
Supplemental fields
ProcessedPID
Updated
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I'll[ SSUItE_[�IS�I�IZItiU�l�lON Sl S"I LM c,��„t��xtil�� �ahrir <br /> 1 Sc lert numh��r ��f F,erforated latc�rals � � „ <br /> --- - -_ __ _ 4uart�r inch E�erl�ttahc�ns s act�1 N1,1 1`' <br /> 2. Select perforatic�n spacin�; = 3 feet. v"of ro�k <br /> 3. Since perfc�ratic�ns should not be placed ric�sc�r t}Zan 1 ft. to Pert Siz�r,g 7/:��'" - �/�� <br /> the edge of the rock layer (see diagram), subtract 2 ft. from �'erf Spa�►nR 15- 5� <br /> the rock layer length. <br /> R�dy3i�,�r, - 2 ft. _ � � feet. <br /> Reqwted Perfomm�D�scharR< <br /> 4. etermine the number of spaces between perforations. �R�«����««m� <br /> Divide the length above by perforation spacing and round D�rg� <br /> Hud �.,^d'r" � p.. <br /> Ifeal � , <br /> down to nearest whole number. <br /> 1.Oa 0.56 0.74 <br /> Len th erf. s acin 2.Ob 0.80 1.04 <br /> g p p g = �` ft. = 3 ft. = 2� spaces <br /> �3� �2� a.Use for single facruly homes <br /> b.Use for all other applications <br /> 5. Number of perforations is equal to one plus the number of <br /> perforation spaces . <br /> U Ma�cimum number of quar:er inch perforations pe <br /> spaces + 1 = �_perforations/lateral lateral to guamantee<10%discharge variation <br /> Perforation <br /> 6. Multiply perforations per lateral by number of laterals to Spf etjg 1; 1 z 2 <br /> get total number of perforarions. 2,5 14 18 2$ <br /> �5 x ��_ �_perforations. 3.� 13 17 26 <br /> 3.3 12 16 25 <br /> 7. Determine required flow rate by multiplying 4.� 11 15 23 <br /> number of perforations by flow per perforation 5.Q 1Q 14 22 <br /> _�✓ � <br /> �� X �� _�gPIIl. wunw�o wcn� nr cw o� v�swc oma,e�na« smEM <br /> 8. If laterals are connected to header pipe as shown on upper _ � <br /> � :,=� � � . <br /> example, to select minimum required lateral diameter; enter _ <br /> table with perforation spacing and number of perforations ,���s„��`� �-�-- �' <br /> per lateral. Select minimum diameter for � ��,`" <br /> perforated lateral = 2— inches. � <br /> ...e,., a .� .,�A,.,>.� <br /> ..�.,�o�;.�.,,,w ...�...� <br /> � .._a,.�...�,..� <br /> 9 If perforated latera] system is attached to manifold pipe near =�� �- ``�'�`"'� "��� � <br /> ,i_� <br /> .,.:.�a� <br /> the center, lower diagram, perforated lateral length and - ��-�,,,K„, ��-- ; <br /> number of perf<�rations per lateral �vill bE� approxiinately one ° --� ..,�,��._ <br /> half of that in step 8. Using these values, select minimum '., `t, °�� <br /> diam�tc:r fc�r F���rfe�rated latc�ral = _ I � _ inches. ,�� .- '� ..� <br /> —y���- . ,�. A n.'.a�..r. <br /> � <br />
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