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�a� 6 <br /> • . � . MOUNT) I)I�:SI( :N WOIZhti11[�(�1 ���'����" �'� <br /> (F�,r I�l������ u�, t�� 1?O(1 �j,�1) <br /> n. �-1.���N — ---� I <br /> I_suma�cd S�waRr Flows�n Gallons�i dav <br /> �5 t 1 Il l�l�t'lj � �d I Nvmbn I Typc 1 TyPe l►) Typc IIl Typ� <br /> <�r rneasured x 1.5 = _ gpd � ��' rv <br /> � �oo izs i so —-- <br /> i 45� 100 21A � <br /> f3 SEPTIC TANK LIQUID V(�LUMES , � „s Z� o« <br /> i s �so aso zva �''"� <br /> _�-�f�q2__ gallons � ,, 900 525 ,,, � �^ <br /> � � ioso I boo 3�0 ' ir�`� <br /> x izoo I ��s I ,,� I uT« <br /> C. S1�1L5 (refer to site evaluation) �<<��� <br /> � T�a4 w�xi1u NMwi <br /> 1. Depth to restricting layer = -3"� inches �7 g feet �ywa��x,,, <br /> Nunn�,��� W e�mum l�uw ��W'4�{'nn•,,n �.,u�mt�w6� <br /> 2. Depth of percolation tests = /'Z �C}1�5 �....�, �n„ s„�,��a,�,�„ ,,h„�,� <br /> 3. 7�exture /02.^—� Percolation rate�.s.3d_ �"�"` 730 "�' ;500 <br /> Ip�j �.�• �o00 �soo .000 <br /> 1.��n 1500 _2S0 �p�p <br /> 4. Land slope _� % - .,,,� z«x, �� ,�,� <br /> D. ROCK LAYER DIMENSIONS <br /> l. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �_gpd x 0.83 sq- ft-/gpd = �3o sq. �. <br /> 2_ Select width of rock layer (max 10' if <120 mpi max S') _ _�_ ft. <br /> 3. Length of rock layer = area — width = �e a ,00, Aa oop� <br /> 6 3 o sq. ft. — /U ft. _ ___�_� ft. ��oo aD�D�doQQa �• �-t� <br /> da�o°�O d�op.OppDaD tp xD., <br /> Wld�e /� ft vo� �a�o�e �bG00-QOD �a o D , <br /> <120mpi <10' �n��_�� <br /> E. ROCK VOLLJME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; sq. ft x <br /> ft. = cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> cu. ft. =27 =�?�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; cu. yd. x 1.4 <br /> ton/cu_ yd. _ � to�, <br /> F. ABSORPTION WIDTH Absorp000 wdth Siung Table <br /> l. Percolatio rate in top 12 inches of soil is���mpi �d,��w��o �,,�� a,�o�r„�«, <br /> Texture � M�nwa per loch Soil Tczturt per day pQ w�di6 io Rock <br /> — (MPI) sqiurc(oa Laycr Wid[h <br /> Fu�rr d�an 0.I Co�rx Sand 1_'0 I 00 <br /> 2- SelE�ct allowable soil loading ratc from table; o;��: F��'s�,e o�ao ;0000 <br /> � �l r 6 io i5 S�ndy Lnam 0�9 1 57 <br /> ��1 t' 16 w iG L.avn 0 60 2(Xl <br /> 31 l0 45 $III(.O]II1 �.SQ ?JQ <br /> 46 Io 60 CI]y L.oaai 0 dS 2 67 <br /> 60�0 120 Clny 0 24 S W <br /> 3. Calculate ads<�rptior� width ratio by dividin� r�ck layer s�o�w��zo c��� o,o eoo <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ftz= gpd/ft� = 2. O <br /> -� Multi}�I�' �3dti��r��tic��i� �,�iclth rat��� h�� rc���l. la1'c�r ���tdth t<i t���t <br /> reyuired ads<�rplion width, � <br /> ��- a --,��-- ft =0��_ ft <br />