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<br /> P11MP SELL-5.714N1'1�SV�EllURI
<br /> (�.p P�Rf(H7A11(N1 (Y A P(-RfO(tATED L4TFRql
<br /> A. [)ctcrmine pump capacity: _�„��,,,,
<br /> (;ravity Distribution ��`��! �-1
<br /> l. Minimum su��c�leci is 6(X)gallons��n c�iur l lU};I�m) t�i slay ahi�ad ol . .���ti.,w`�N � �
<br /> watcr utic�ratc. �--^�°�^^� ����,�����..�:..,;
<br /> 2 Max�mum su�estcd for delivcry to a dre���tx�a<�I a hc�rn��syst�m is 2,700 'T _:�s�`" -N������•,.�.,a,,,
<br /> gallorLs per hour(45 gpm)to prevent build-up of pressure in drop box. �.,-A,„ � -., �.,,, ,z•„�,a,
<br /> wie er R«��„
<br /> w�wa�.�.�m�w a�
<br /> Pressure Distibution �,,.,,�„1ej� H-��«�..�..,�
<br /> 3.a. Select number o(pecforated laterals __ �___,,__
<br /> b. Select perforation spacing= feet_ `«�«���� ^�•����
<br /> e.�a..rba..a sw�o.«
<br /> c. Subtract 2 ft from the rock layer lengih.
<br /> µ,���, -2 ft.= feet
<br /> d. Deternune the number of spams between perforations.
<br /> Length perf.$p3Cing= ft. + ft. = spacCs Requved Perforation[��t,��e
<br /> e. _spaces+ 1 = perforations/lateral ��uo�p�n,in�ce(gpa,r
<br /> f. Multiply perforations per lateral by numt>er of laterals to n�t�e
<br /> get total number of perforations. ���. x-T;�-;_ __ Perforations. �f�j �2 md� ' �dP`"
<br /> ,,�.,
<br /> � �Q++x X aim�r-={- gP�' - ---
<br /> I.Oa � 0_56 0.74
<br /> SELECtEI) PUMP CAPACITI" LO-_`��pm 2.Ob ! 0.�0 1.04
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<br /> B.Determine head re4uirements: a. L'se for single family homes
<br /> 1_ Elevation difference between pump and point of disctiarge. b_ Use for all other applicahons
<br /> �__feet
<br /> 2. If pumping to a pressure distribution system,five feet for pressure
<br /> required at manifold if gravity system,zero.
<br /> _�_feet
<br /> 3_ Friction loss
<br /> a. Enter friction loss table with gpm and pipe diameter. Pipe L.aigch �
<br /> Read friction loss in feet per 100 feet from table. � '
<br /> Point of Discharg<
<br /> F.L= �I � k./100 ft of pipe
<br /> b. Determine total pipe length from pump to discharge p���;�,D;�{�,�T
<br /> point_ Add 25 percent to pipe length for fitting �p 1
<br /> loss,or use a fitting loss chart. Equivalent pipe
<br /> length- I25 tirnes pipe length= F-18b
<br /> 120 x 1.25= ►33 feet
<br /> c. Calc,ilate total friction loss by multiplying 1-��m 1�'0�ch 3.0 inch
<br /> g�� pc 100 fi o[P�pc
<br /> friction loss in(t/10(?h by equivalent pipe length.
<br /> Total friction loss= l"�'� x 1 .) � +100=�_feet 10 0_69 o.20
<br /> 12 0.96 0.28
<br /> 4. Total head required is the sum of elevation difference, 14 1.28 0.38
<br /> special head requirements,and total friction loss. l6 I_63 0.48
<br /> 18 2.03 0.60
<br /> 1 + V � 2 20 2.47 0.73 0.31
<br /> �y�5 3.73 _],,1,1 0.16
<br /> (1) (2) (3c) 30 5.23 LSS 0.23
<br /> 35 7.�?0 2AG 0.30
<br /> 4f) 1 1-07 2fi4 039
<br /> TOTAL HEAD _ _1-� ___- feet a5 la 7� 328 0.48
<br /> SO 3.99 O.SR ,
<br /> 55 4.76 OJ(I i
<br /> C Pump selection �� s� j �82 �
<br /> _ _�
<br /> �
<br /> � � 1. A pump must be selected to deliver at least
<br /> �S_ fi�m (St<��� /1) ���ith at lc�a51 ��__ Ie��t �( total hcad (�t���� fi)_
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