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. � t <br /> � - � PRE�SURE L7�STRIBLTI'IpN SYSTEM , <br /> Geotextile lfabric <br /> 1. Se]ect number of perforated laterals 3 ! � <br /> - . i�—2-! -y <br /> 2� Select perforataon spacing = 3,c7 ft ° <br /> ---- of,.rocic j <br /> 3. Since perforaHons should not be placed closer than 1 foot to I'erf Siziaig 3/76��_i�4.. <br /> t11e edge of the rock layer (see diagram),subtract 2 feet from I'erf Spacut�1.5'-s' <br /> the rock layer length. <br /> E-4: Ma��imum allowoble number of 1/A-inch pertorc��pions <br /> . Rock layer engUi -2 j t - <br /> �� ft Pe►�aleral to guarantee<t D%discharge variafion ' <br /> perforafion <br /> 4. Determine the nuinber of spaces vetween perforations. SPacing <br /> D�vide the Iengtln (3) by perforation spacing (2) and r Lu-i ��e� 1 inch 1.25 inch 1.5 inch 2.O,inch <br /> down to nearest whole number. � <br /> PerforaHox�spacing= (�(.� ft • 2.5 8 14 18 �a <br /> 5. Ntunb f�f t= c��? spaces 3.0 8 13 17 <br /> er of perforations is equal to one plus the number of ~�6> <br /> 3.3 7 12 16 _ _ � i. <br /> p�rforation spac�es(4). Check figut�e E-4 to assicre tlze number of 25 <br /> 4.0 7 il 15 23 <br /> pe�forntioris per Interal guara7zfees <10% discharge varintio�i. 5�0 6 10 �q <br /> 22 <br /> �_spaces + 1 - '�, 1 perforations/lateral -- _— � <br /> 6. A. Total numb�es of erforations = E'd� P�rfo�ra9iorn Discharge i—_n�pm <br /> P perforations per lateral (5) <br /> times number of laterals (1) perforation diameter <br /> I) head �nches ; <br /> ��Lperfs/lat x�_lat=�_perforations <feet) �/16 7/32 1/q I <br /> 1�. Ca�culate the square footage per perforation. �'�� 0•42 0.56 �,74i <br /> Should be 6-10 sqft/perf. Does �1ot app1J to at-grades. 2•0b 0.59 0.80 1.04i <br /> Rock bed area = rock width (ft) x rock length (ft) ' <br /> 10 ft x �. � 5�0 0.94 1.26 1.65� <br /> ��_ft=- G��sqft <br /> Square foot per perfora Hon =Rocl<bed area+number of erfs 6 � Use 1.0 foot for single-fomily homes. <br /> _ (��) sqft=�_ P � � b Use 2A feet/or an hln else, j <br /> perfs = 9,0 sqft/perf <br /> 7. Deternuzte required flow rate by mu]H j � M4NIF0�0 LOC4TE0 AT ENp pi ppE55UqE DISTpIBUTIDNI5y5TEn� <br /> perforations (6A) by flow per perfoxa on (sge figY��e E-6�ber of <br /> �J n. <br /> �perfs x .-�-gpym/perfs =—�Z m �.,� <br /> � ;��-,:o. <br /> 8. If]aterals are coruzected to header pipe as shown on upper ° <br /> exam le to select ��•" <br /> P � Inulimurri required lateral diameter;enter �`"` I�"^'�•,a-� <br /> d��Ni�� .A;.":w. •c <br /> igure E-4 with perforation spacing (2) and number of perforaHons i <br /> \� „�� <br /> per lateral (5) Sel�ect minimum diam�eter for � <br /> perforated lateral=�_jn�eS. u.ou, F pEPfORnTEO P1PE laTEflnLS roa <br /> PRESSUPE U�STPiBu110N W u0UN0 <br /> 9. If perforaled lat�eral system is attached to manifold i e near R � <br /> the center, lower diagram,perforated lateral 1 P p EN�""`on `o " c°ra`� �y.`"" ' <br /> ength (3) and ��Fw ;q�;�Ws`e��..e�., ,.- �.�a,o,.,,o <br /> numb�r of perforations per lateral (5) will be approximately one Y°`'�`° <br /> half of that in st�ep 8. Using these values, select rtunimum � °""`�"".��.��'. ,�'- <br /> � � <br /> diameter for perforated lateral = ��ches. <br /> l�a�.. b, i�r�n����l^'c.no�I,,...� <br /> � / � rrvnRto �w..�. <br /> \\ ����M d� '�•• n <br /> \� <br /> I]�ereby certify that I have c pleted this work in accordance with applicable ordinances, i-ules and laws. ' <br /> � <br /> � f <br /> �� (signah�re) _ 3°J� (license#�) ��a�� � <br /> ______.L_(da te) <br />