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2003-P06380 - septic
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440 Brown Road South - PID: 03-117-23-42-0012
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2003-P06380 - septic
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Last modified
8/22/2023 4:38:18 PM
Creation date
2/4/2016 2:01:06 PM
Metadata
Fields
Template:
x Address Old
House Number
440
Street Name
Brown
Street Type
Road
Street Direction
South
Address
440 Brown Rd S
Document Type
Septic
PIN
0311723420012
Supplemental fields
ProcessedPID
Updated
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� � MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> Estimated ���%�% gpd N�f� 7,�, TyptD) TypeID T� <br /> or measured x 1.5 = gpd. <br /> 2 300 225 180 � <br /> B. SEPTIC TANK LIQUID VOLUMES a � s00 is6 °f� <br /> ���� <br /> ��>e%�j gallons 6 '�050o su s�z T'" ,. <br /> � I050 600 370 � <br /> IIm <br /> 8 1200 675 608 � <br /> C. SOILS (refer to site evaluation) `°'"""� <br /> ' lic Tank G auties f in aUuns <br /> 1. Depth to restricting layer =_���inches =�- feet ,;qW,�,��„y <br /> NmMer�if Minimum liyuid liyuid tapaary witA wi�h disposal& <br /> 2. Depth of percolation tests = lZ inches B�^•�^u ca���r e�as�d=v�� ��h���� <br /> �`�/w. 2�x less 750 1125 I500 <br /> 3. Texture Percolation rate �G�mpi �.,<< <� ,5� z� <br /> 5 nr 6 1500 2250 3000 <br /> 4. Land slope /v % �'R m y 2� 3� � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> .�E'�t> gpd x 0.83 sq. ft./gpd =sc,r� sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = i�� ft. <br /> 3. Length of rock layer = area-width = > adeee� sa�o �e.ea <oab� �, o <br /> 4c- [ �° /'� � <br /> o �o A <br /> � C.�'/% .Sq. ft. - .�1L. - t, /% lt. 04:�ooDb`.l^.bYptl�Da-bp4a p�'. _ <br /> qe'odod_qa'�.e ceeaa,c <br /> : .o�o'ao'aooD<nD Dp:-:. <br /> Width ��. ft °a Ao odoaopoa D anD;. <br /> <120mpi <10' Length _S�_ ftp <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;-5��� sq. ft. x_� <br /> ft. _.�• c;es cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��ic'C% cu. ft. =27 = �-� cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; z��� cu. yd. x 1.4 <br /> ton/cu. yd. _ ��tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is /�- mpi ����,�;� Gallons RarioofAbscvpuon <br /> Mioutes pa Inc6 Soil Tezhue per day per width to Rock <br /> Texture L�'.��t'� (MPi) <br /> �y�r�c �y�wam <br /> Faster than 0.1 Coarse Saud 1.20 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; o.,�o s Fne Sand o.6o z.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> ; c�r� �d/� � co o ��,,, 0.6o z <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�o„�w��zo c�ay o.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ftz= A f.C^ gpd/ft2 = Z-�`< , <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> Z x ir:, ft = 2�= ft <br />
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