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� OSTP Pressure Distribution , _� <br /> � LINIVERSITY - <br /> Minnesota Poliution Des�gn Worksheet OF MINNESOTA ` �y � <br /> Control Agency �,.*.�� <br /> 1. Select Number of Perforoted Loterats in system/zone: C_J Geotextlle <br /> ��0�70�D����.�DB�OOpD�RD� Mi�imum��VO ��tp�Oppg <br /> �1 fe2t)5►i1TR1R7UlR QI1CI 3 fE'Bt IS li1QX1fT1U111 S�CIRg� oc'!:"perforations spaced 3;apart r�q 2'of rock o 'e�agp o <br /> ��A <br /> 2. Select Perforation Spocing: 3.0 f[ o a�yj o�bcb o�o�o�;��o��n 0"q�oorj o-_ �Z" <br /> o°doo'�oo°�onoo'�o°doo�6� i.�.�4Yck�o'doo`�o"�dp� '�°o <br /> oo,o�cFoo-�y�oo�oaonoo�mo� 9 ofrock+�0�'D�aDo��q�",�o�o�o <br /> '�o"�o�o°��o"�o`�oo"� �o"�o`�o`�o�o"�ScT �`0�60" <br /> 3. Select Perforation Diameter Size 7/32 inch Perforation sizin ,,•�o��.- <br /> 9� <br /> Perforation s aci :2'to 3' <br /> 4. Length of Latero(s =Media Bed Length-2 Feet. Perforation can not be closer then 1 foot from edge. <br /> 63 - zft = 61 ft <br /> 5• Determine the Number oj Perforation Spaces. Divide the Len�th of Latera(s (Line 4)by the Perforntion Spocing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- �3 �ft = 20 Spaces <br /> 6. Number of Perforations per Latera( is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check Tab(e!to verify the number of perforations per lateral guorantees less than a 10%discharge variation. The volue is double if <br /> the a center manifo(d is used. <br /> �• Total Number of Perforations equals the Number of Perforations pe�tateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Perf. Per Lateral X �3�Number of Perf. Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Squnre Feet per Perforation. Recommended value is 4-10 ft 2 per perforation. �,,a,d�,�,a���M� <br /> Does not apply to At-Grades -- ,�,,,„�,DiTe1� <br /> Nead ifq ��. �/. '/.. '�. <br /> Bed Area = Bed Width(ft)X Bed Length(ft) � <br /> 1,0' 0.18 0.41 0.56 0.74 <br /> 10 ft x 63 ft = 630 ftZ +-5 0.== o.s, �.69 0.9 <br /> 2.0� O.I6 0.59 0.80 1.04 <br /> 2.5 0.39 0.65 0.89 1.17 <br /> Square Foot per Perforation =Bed Area divided by the Totn!Number of Perforations (Line 7). 3.0 0.3: o.�: o.9a ,.26 <br /> a.o o.;� o.as ,.,s ,.,� <br /> s.o' o.at o.e� t.zs i.es <br /> 630 ftZ .- 63 perforations = 10.� ftZ/perforations „�� ��4�^�hand3/toirrchperlorotionson <br /> �_dweltings <br /> 9. Select Minimum Average Head: 1.0 ft I t/8 inch perforatiartt on Aveilings and for <br /> I 2 teec other establishmena <br /> i <br /> � 1/4 in:h atd 3716 inCh pefOfa[iorrs an M57S <br /> � 5 feet ti�8 inch perforations on M5T5 <br /> �___._._ .-___..__.._______-___�_-______._- <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• Determine required F(ow Rate by multiplying the Total Number of Perforotions (Line 7)by the Perforation Discharge (Line 10). <br /> 63 Perforations X 0.56 GPM per Perforation = 36 GPM <br /> 12. Select Type of Manifold Connection (End or Center): � end ❑ center <br />