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. S � L_ � OSTP Non-Level Pressure Distribution UNIVERSITY ` �' �,��` Minnesota Polluiion `�" `'�'�-;' Design Worksheet OF MINNESOTA �,,,�� Control A enc � Laterat 3 GPM=Length of Lateral X Gatlons Per Minute Per Foot(Line 8) �O ft X 0.30 GPM/Ft= O.O GPM Number of Perforations=GPM/Ftow Rate for Laterat 2(line 6.3) Check Table to ensure the maximum number of perforations is not exceeded. 0.0 - Q = #VALUE! Perforations Select Type of Manifold Connection (End or Center): Spacing=(Length of lateral)/(Number of Perforations-1) ❑ E"d ❑ Cente` (� ) - ( #### Perforations-1) _ ####ft Lateral 4 GPM=Length of Lateral X Gallons Per Minute Per Foot(Line 8) � ft X 0.30 GPM/Ft= O.O GPM Number of Peeforations=GPM/Flow Rate for Lateral 2(Line 6.4) Check Table to ensure the maximum number of perforations is not exceeded. 0.0 .- � _ #VALUE! Perforations Select Type of Manifold Connection (End or Center): Spacing=(Length of Lateral)/(Number of Perforations-1) ❑ E"d � cer'te` (� ) � ( #### Perforations-1) _ ####ft Lateral 5 GPM=Length of Lateral X Gallons Per Minute Per Foot(Line 8) �O ft X 0.30 GPM/Ft= O.Q GPM Number of Perforations=GPM/Flow Rate for Lateral 2(Line 6.5) Check Table to ensure the maximum number of perforations is not exceeded. 0.0 .- � _ #VALUE! Perforations Setect Type of Manifold Connection (End or Center): Spacing= (Length of Lateral)/(Number of Perforations-1) ❑ E� ❑ cen�er (�0� 1 � ( #### Perforations-1) _ ####ft 10. Calcutate Total GPM for system-the total GPM need from the pump. Lateral 1 Flow + Lateral 2 Flow + Laterat 3 Flow + Lateral 4 Flow + Lateral 5 Flow = Total Flow�+,I fl.I x 3_Sy.3 0 C� 0 0 0 = �� -�rA 9.0 + 9.0 + 0.0 + 0.0 + 0.0 18.1 11. Summary Enter the minimum pipe size that altows for even distribution and the volume of liquid in the pipe from Volume of Liquid in the table. �Pe Total Volume Pipe Liquid Pipe Volume Pipe Length to Fitl Pipe Perforation Diameter Per Foot Pipe Size(in) (gal/ft) (ft) (gal) Size (in) Spacing(ft) (inches) (Gallons) �aterall 1.5 0.110 30 3.3 7/32 2.0 Highest 1 0.045 �aterat 2 1.5 0.110 30 3.3 7/32 4.5 1.25 0.078 Laterat 3 0 #VALUE! 1.5 0.110 2 0.170 �aterat 4 0 #VALUE! 3 0.380 Lateral5 0 #VALUE! Lowest 4 0.661 Total Volume of Distribution Piping= 6.6 ;/ f = � 1? Min.Detivered Dose Volume=Five X the Total Votume of Piping= 33.0 ,J i M �9 ,U � I hereby certify that I have completed this work in accordance with all applicable ordinances, rules and laws. :•'� �.... _.- Joseph J Olson �� 810 05/10l11 (Designer) �-'' ` (Signature) (License#) (Date)