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OSTP Mound Design [JNIVERSITY <br /> Minnesota Poilution W��-k����t OF MINNESOTA � � � <br /> Control Agency `"�� <br /> 1• SYSTEM SIZING: <br /> A. Design F(ow(Design Summary tA): 375 GPD Table 1 <br /> IdOUND CONTVUF LOAD�NG�ATES: <br /> B. Soi!LOading Rate (Design Sum.2D): 0.60 GPD/ftZ �,»surad ' ToxturQ-derived Contour <br /> Parc Rato �R mound atrso�ption ratio Loading <br /> C. Depth to Limiting Condition: 1.7 ft . �LQ� <br /> D. Percent Lnnd Slope (Desiqn Sum. 28): 12.0 % '=SQrnpi I.0, i.3.2.0. 2.J, 2.6 _72 <br /> E. Design Media Loadinq Rate: 1.2 GPD/ft2 5i-t20 mpi �R s.o _,z <br /> F. Mound Absorption Ratio: 2.0 � izo n,;,;• -s.o• _s� <br /> G. Design Contour Loading Rate: 12 GPD/ft •Systems with these vatues are not Type I systems. <br /> (From Design Summary 2E-same as Linear Loading Rate) Contour Loading Rate is a recommended value. <br /> 2. DISPERSAL MEDIA SIZING <br /> A. Calculate Required Dispersa(Bed Area:Design F(ow (1.A)=Design Media Loading Rote (1.E)=ftZ <br /> If a larger dispersat media 375 GPD: 1.2 GPD/ftZ = 312.5 ftZ <br /> area is desired,enter size: 320 ft2 <br /> B. Calculate Dispersal Bed Width:Contour Looding Rate (1.G)=Design Media Loading Rate (1.E)=Bed Width <br /> 12 ft : 1.2 gpd/ftz = 10.0 <br /> C. Calculate Dispersa(Bed Length: Dispersal Bed Area (2.A)=Bed Width (2.6)=Bed Length <br /> 320.0 ft2 = 10.0 ft = 32.0 ft <br /> D. Select Dispersol Media: <br /> 3. ABSORPTION AREA SIZING <br /> Note:Mound setbacks ore measured from the Absorption Area. <br /> A. Calculate Absorption Width:Bed Width (2.6)X Mound Absorption Ratio (1.F)=Absorption Width <br /> 10.0 ft X 2.00 = 20.0 ft <br /> B. For slopes from 0 to 1%, the Absorption Width is measured from the bed equally in both directions. <br /> Calculate Absorption Width Beyond the Bed:Absorption�dth (3.A)-Bed Width (2.6)-*2= �dth beyond Bed <br /> ( N/A ft - N/A ft) :- N/A = N/A ft <br /> C. For slopes>1%,the Absorption�dth is measured downhill from the upslope edge of the Bed. <br /> Calculate Downstope Absorption Width:Absorption Width (3.A)-Bed Width (2.6)=ft <br /> 20.0 ft - 10.0 ft = 10.0 ft <br /> Comments: <br /> S(ope, CLR Choice,Materia!issues <br />