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�, � MOUND DESYGN WOYZ�CSIHECT --• �_�-Sf�� �1i�'a�✓�+.� ,���?
<br /> � . . (For Flows up to 1200 gpd) � y� �
<br /> , .�C���'1c1� � ►I N
<br /> �_....,._...r,�..,_ _..�..,_
<br /> A. �l.O W / � (�/ \ � �.iUU aiW ���C Y�Gwf!.P li ' .P.,3 ua,
<br /> / � I/ l ..-.....1.�'Kll
<br /> . Estimated �c�� gpd � u�r �c.crY+-� � �;w.r„i�r ,iba 1 7ytuu yTpc�; Ty,.
<br /> ; � �
<br /> or measured x 1.5 = gpd. ��«� i
<br /> � �
<br /> __. ,_._.y.._.
<br /> 2 ,� � �n., ur�
<br /> B. SEI'TIC TANK LIQUID VOLUMES � �.:: �"�'`��' :',� '"�'
<br /> � �- �'j , wsu �� �a,.x.
<br /> '7' �' �(�pU gdll�� SjZ � Gcsn���i) i 6 � •ri1 S"1S 33? ,�.r�.
<br /> � 7 ' I�i•,; bp 3 �� �
<br /> y � t;:.xi I b�5 �� �Ii}n � �tfi
<br /> C. SOILS (refer to site evaluation) � - � _...�:.,.;......� '""'"""
<br /> / �.voc T.�... ..r ,,„.ny,,,._.
<br /> l. Depth to restricting layer= �_ inches ��� feet ` "�
<br /> �,,,,��. _,
<br /> N��uc,r�N .�.�wwl+r�«.i :�.,W.a�pMca,rwu� ..�n�,�.,...�..
<br /> 2. Dept11 of percolation tests = 1� inches 6���a �i � t��«,-�•� u«�w<. "
<br /> 3. Texture �a-�-��-� Percolation rate �Z►, t�, mpi �i�"`�' �-. ��:, � _;'"'
<br /> s„�� -nr�o- z_�-.�
<br /> �.n w v 1W(r 1.�x� s
<br /> -�. Land slope �' °�a � ���
<br /> _-..,,,........,.._.r _
<br /> D. hOCK LAYER DIMENSIONS �
<br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A ;: 0.83 =
<br /> (�� gpd x O.b3 sq. ft./�pd =�� sq. ft. w ��")� - �5u �.�{'�'-_
<br /> 2. Select width of rock layer (max 10' ir <120 mpi max 5') _ �ft�
<br /> 3. Length of rock layer = area -width = �� /� ��j...�d � n �•Q{ -:��- � - ,
<br /> �����v S(] l l. �i' �� j�. � ���,.J �`. 'i'�O', �u L')�LI� CJpL,Q� "U�.. �rtw� K'�p"��..
<br /> +� q�oa°oc: tla�:.�„ci,uA•D yp :`f�"b'V2� ¢�..+�..�-•-..,, �.
<br /> Width c� ft � -�1--0� G---;�-,�.�nF."�-
<br /> <120mpi <!0' 1_�:iigt,h �"�,.,�;,,�,;t
<br /> E. P.00�:VOLUME
<br /> >120mpi <5'
<br /> 1. Multiply rock area by rock depth to get cubic feet of rock;���� sq. rt. x!�
<br /> ft. -�G cu. ft.
<br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards;
<br /> J�
<br /> J` �G CU. �. -- 27 = ..2 / CLI. YC�.
<br /> 3. Iviultiply cubic yards by 1.4 to get�veight of rock in tons; <� I cu. y�i. x 1.-1
<br /> ton/cu. yd. = 3� tons. �-�G��G
<br /> F. ABSOl'.PTION WIllTH ,tiw��,,,,.�ww4.�:�t.,,,��rx:E�. L+
<br /> l. Percolation rate in top 12 inch�s of so:l is ���(� mpi NLCCW.WW I4t W Ci,,,� ��,;,..�,.,,.,. ;
<br /> Texture �GYr n1. M�uu�,ycr lu�:b S.�,I'icxtucc :�l.y,,.r w„iJ.�.�r..,..
<br /> U✓�Ct.)�J`-�� fr, P j �(lY�c�f� (MYl) _ �:y�:uC kl.x lYyc� Iti_;_.�
<br /> 1 ""..
<br /> F:u�cr�tww o.l C,.....:Saoa 1.�0 (.ln;
<br /> O.I w� :..uJ 1.:U I U!
<br /> 2. Select allowable soil loading rate from table; o.�W s F,..;,,�, o�a �u,
<br /> �o,�_ S»..,. � p.79 i 7:
<br /> ,� G,�, �pd/f� ���� � �:.��' -��.a �:.
<br /> . 31 w a i ...�..+irn -__.D"5� ...x;
<br /> J6 W 4�1 1.�.,r i-l+iWt U.�S �.O]
<br /> OU w 1_0 .:�y (1.7..i 1��,
<br /> 3. Calculate adsorption width ratio by di��iding rock layer s'°"'a°,-"10 ,;'-Y °�' °�°,
<br /> loaaing rate of 1?0 gpd/ft?by allowat,l� soil loadin; rate; �� ��
<br /> 1.20 �pd/ft2-: .4��- vPd�ft2 = <-;�, d c:
<br /> 4. Multiply adsorption width ratio by rocic layer width to get
<br /> required adsorptian width;
<br /> �,� ,�oX 1C� ft = �� ft
<br /> � _ __ __.__ _._.__ _. _ . l
<br />
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