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Brown Road North
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809 Brown Road North - 27-118-23-34-0006
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Last modified
8/22/2023 4:21:22 PM
Creation date
1/26/2016 1:32:15 PM
Metadata
Fields
Template:
x Address Old
House Number
809
Street Name
Brown
Street Type
Road
Street Direction
North
Address
809 Brown Road North
Document Type
Septic
PIN
2711823340006
Supplemental fields
ProcessedPID
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_ ' <br /> � <br /> i , <br /> . • � • MOLND DESIGN WORKSHEET <br /> � - (For Flows up to I200 gpd) <br /> a. �,Q�J Estirnued Sewage Flow in Galloc�s per Day(gpd) <br /> ' Estimated �.�0 gpd N�� <br /> of Type 1 Type II 'iypc JII Type IV <br /> or measured - x 1.5 = - gpd. a��� <br /> 2 300 225 180 cas <br /> 3 450 300 218 °t <br /> B. SII'TTC TANK LIQiJID VOLUMES 4 �0 3�s z� .��. <br /> 5 750 450 244 � <br /> 1-I�S� v- 1-i oo� g�0I1S 6 900 5?S 332 �'� <br /> 7 1050 600 370 °�"` <br /> F,�-�Y� s tzoo 6�5 aos `°'°s' <br /> C. SOILS (refer to site evaluation) '� � �`' �� �y� <br /> x�bc r.ti� �� <br /> �I �I of sq�c Tmt Cy.�Fw <br /> 1. Depth to restricting layer = i a � ��► inches �� �,,. �,, <br /> 2. Depth of percolation tests = i a" inches `'�`' `p"m'' <br /> 3. Percolation rate J S.�� mpi 23 a`a� ,'o�o°o ;:'so�o <br /> 4. Land slope � %a ;Q 8 z� 3� <br /> wc 9 See fig.C-6 (z IS) <br /> D. ROCK LAYER DL�v�TSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = p� <br /> � v . gpd x 0.83 sq. ft./gpd = c��� sq. ft-��o�u=��`► <br /> 2. Select width of rock layer (10 feet or less) _ /� ft. <br /> 3. Length of rock layer = area=width = Rock Bed <br /> ���sq. ft.-:- i o ft. _ �� ft. �.ti.�.,.�.ti.�.�.ti.�...�.�.�.�.,.ti <br /> r•f•f•�•f•f•r•r•f•f•r•r•f•r•f•f• <br /> ti.ti•ti•ti•ti•ti•ti•ti•ti•L•L•1•L•ti•ti•ti•t <br /> tiftif{:{{tifti:tiftirti:tirtiftiftirti:tifti'•{ idth <_10 ft. <br /> ti�tifti�ti�ti�tiftiftiftiftiftirtir�!tifti?t�1 <br /> .�.f.f.f.f.f.r.f.f.f.f.f.f.r.r.f. <br /> E. ROCK VOLUME ~- �ng�' -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> b�I sq. ft. x �.a� f t. =Z cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��� cu. ft. i 27= a�cu. yd. � <br /> 3. Muliiply cubic yazds by 1.4 to get weight of rock in tons; <br /> �'� cu. yd. x 1.4 ton/cu. yd. _ � � tons. <br /> F. ADSORPTION WIDTH �-`-'�`� L'ei�� Ab�tia,w�a�;s�, Table <br /> 1. Percolation rate in top 12 inches of soil is � '. mpi r��,ba,R,� �°� R�°°°' <br /> ,,��,,,(m�;�, SoilTexture �.�� � <br /> P t� . <br /> ��� <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.20 l.00 <br /> � d/ft� 0.1 to� Sand 1.20 1.00 <br /> ,`�S � 0.1 to 5 Fine Sand"` �•� 2-� <br /> 6 to 15 ndy Loam 0.79 la2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 to 30 Loam o.bo 2.00 <br /> T� }' g }' 31 to 4� Silt Loam 0.50 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to 6o c�a Loan, 0.45 z.6� <br /> 1.20 gpd/ft�y ,y s� gpd/ft� _ �. �� s�oWe�t��izo ciav o�4 s.00 <br /> "Soil having�04.or more of fine or vay fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> . �,L� x la ft= a�.� ft <br />
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