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. , � MOUND DESIGN WORKS�IEET
<br /> ' � ' (For Flows up to 1200 gpd)
<br /> A. FLOW Cs�imatcd Scwage Flows in Gallons per dny
<br /> Estimated � ' gpd (see pages D-7 or I-3, 4, 5) , �m�< <g��
<br /> or measured --- gpd x 1.5 = �r Ty�� TYr��� Tyr��i� Ty�
<br /> flcdroom s �V
<br /> B. SEPTIC TANK LIQUID VOLUMES 3 4°0 30�o igg �
<br /> � , 4 600 375 256 ���.
<br /> �> ! � ;�,"�-�gallons (see pages C-3 or C-5) s �so aso zso ;o
<br /> 6 900 525 332 '7��.
<br /> 7 1050 G00 170 �
<br /> 8 1200 G75 408 �d„�,,,
<br /> G SOILS (refer to site evaluation) , ,,
<br /> 1. Depth to restricting layer = /�f -r�,� inch S ScplicLnkGpacitic;ing.lbny
<br /> Numbcr o( \1in'vnum Liquid I.iquid capr:iiy wiJi
<br /> 2. Depth oF percolation tests = I "� incl es ���m, � .�,
<br /> rp ry avb�ee d'upoal
<br /> 3. Percolation rate '"; �, j mpi z«k�� ,� „u
<br /> � Oy 3 or 4 �p(7() �Spp
<br /> 4. Land slope � /0 "''�a6 - ��p �?�>
<br /> �,e a 9 xxz� wno
<br /> , o��s ...... ,
<br /> D. ROCK LAYER DIMENSIONS
<br /> 1. Multiply flow rate by 0.83 to obtain required a ea of rock
<br /> layer: Daily Flow x 0.83 =
<br /> ��_gpd x 0.83 sq. ft./gpd = ;�:-� _; sq. ft. � �F,`S�, = ��,,�i
<br /> 2. Select width of rock layer (10 feet or less) _ )� ft.
<br /> 3. Length of rock layer = Area 1 Width =
<br /> ( si` sq. ft. = , 1 �.� ft. = l,� �;" ft. Rock Bed
<br /> f'f•f•!•f•l.f.f:;:f.f:f.J:l�r
<br /> 1••.••.•ti•ti•ti•ti•ti••..•,.•,.•,.ti.ti.•,.
<br /> f•f•r•f•!•l•r.J•J•!•f.f•f.r•:
<br /> ti•ti•ti•ti•ti•ti•ti•••••••ti••..ti.ti.•.••.• idth S10(t.
<br /> .f.f.f.r,f.f,r.f,f.r,f,r,f,f,f
<br /> , ti,.,,ti,.,,ti,.,,ti,,,,,,,,,,,,,,,,,,,,,,
<br /> E. ROCK VOLUME '"'''f'''f'''""f'''''''"'
<br /> �.• Length --�
<br /> 1. Multiply rock area by rock depth to get cubic feet of rock;
<br /> '.,�- �!sq. ft. x 1. -��; ft. = rj1'''cu. ft.
<br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards;
<br /> �cu. ft. -�- 27 = �� -� cu. yd.
<br /> 3. Multiply cubic yards by 1.4 to get weight of r ck in tons;
<br /> �"�� cu. yd. x 1.4 ton/cu. yd. _ � tons.
<br /> F. ADSORPTION WIDTH �L�-t-( LU�1'3'1
<br /> Absorption Width Sizing"1'ablc
<br /> 1. Percolation rate in top 12 inches of soil is ��_1.'�-s_ pi
<br /> Pcrcolatlon Rmc Gallons Ra1io of
<br /> 2. Select allowable soil loading rate from table on p ge E-; in Minutesp�r Soil Tcxture per day�xr Absorption widih
<br /> �'� gPd�f� fnch(MPI) squnre foot lo Rock Laycr
<br /> Width
<br /> 3. Calculate adsorption width ratio by dividing rock layer F����,�ne�o.� • c�us��,� _____ __.._
<br /> o.i�a s s��� i.zo i.00
<br /> loading rate of 1.20 gpd/ft�by allowable soil load ng rate; o.��os•• FincSand•� o.�o Z.�o
<br /> 6toIS Snnd Lnam 0.79 I.S2
<br /> 1.20 gpd/ftZ-t- � '-I . gpd/ftZ= � , !.. � ie�o�o �„�, 0.6o z.cx�
<br /> �i�o as su��,��» o.so z.ao
<br /> Check tliis value on page E-16. 46�a�, ClayLomn o.as z.�,
<br /> � 60 l0 12tl Clay 0.24 S.IM)
<br /> 4. Multiply adsorption width ratio by rock layer wi th to get s�oWe��nr� c�,y ...__ __.._
<br /> t2o•••
<br /> required adsorption width;
<br /> �?.T.,�x � � ft = ='�.�'� ft
<br />
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