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. , � MOUND DESIGN WORKS�IEET <br /> ' � ' (For Flows up to 1200 gpd) <br /> A. FLOW Cs�imatcd Scwage Flows in Gallons per dny <br /> Estimated � ' gpd (see pages D-7 or I-3, 4, 5) , �m�< <g�� <br /> or measured --- gpd x 1.5 = �r Ty�� TYr��� Tyr��i� Ty� <br /> flcdroom s �V <br /> B. SEPTIC TANK LIQUID VOLUMES 3 4°0 30�o igg � <br /> � , 4 600 375 256 ���. <br /> �> ! � ;�,"�-�gallons (see pages C-3 or C-5) s �so aso zso ;o <br /> 6 900 525 332 '7��. <br /> 7 1050 G00 170 � <br /> 8 1200 G75 408 �d„�,,, <br /> G SOILS (refer to site evaluation) , ,, <br /> 1. Depth to restricting layer = /�f -r�,� inch S ScplicLnkGpacitic;ing.lbny <br /> Numbcr o( \1in'vnum Liquid I.iquid capr:iiy wiJi <br /> 2. Depth oF percolation tests = I "� incl es ���m, � .�, <br /> rp ry avb�ee d'upoal <br /> 3. Percolation rate '"; �, j mpi z«k�� ,� „u <br /> � Oy 3 or 4 �p(7() �Spp <br /> 4. Land slope � /0 "''�a6 - ��p �?�> <br /> �,e a 9 xxz� wno <br /> , o��s ...... , <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required a ea of rock <br /> layer: Daily Flow x 0.83 = <br /> ��_gpd x 0.83 sq. ft./gpd = ;�:-� _; sq. ft. � �F,`S�, = ��,,�i <br /> 2. Select width of rock layer (10 feet or less) _ )� ft. <br /> 3. Length of rock layer = Area 1 Width = <br /> ( si` sq. ft. = , 1 �.� ft. = l,� �;" ft. Rock Bed <br /> f'f•f•!•f•l.f.f:;:f.f:f.J:l�r <br /> 1••.••.•ti•ti•ti•ti•ti••..•,.•,.•,.ti.ti.•,. <br /> f•f•r•f•!•l•r.J•J•!•f.f•f.r•: <br /> ti•ti•ti•ti•ti•ti•ti•••••••ti••..ti.ti.•.••.• idth S10(t. <br /> .f.f.f.r,f.f,r.f,f.r,f,r,f,f,f <br /> , ti,.,,ti,.,,ti,.,,ti,,,,,,,,,,,,,,,,,,,,,, <br /> E. ROCK VOLUME '"'''f'''f'''""f'''''''"' <br /> �.• Length --� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> '.,�- �!sq. ft. x 1. -��; ft. = rj1'''cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. -�- 27 = �� -� cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of r ck in tons; <br /> �"�� cu. yd. x 1.4 ton/cu. yd. _ � tons. <br /> F. ADSORPTION WIDTH �L�-t-( LU�1'3'1 <br /> Absorption Width Sizing"1'ablc <br /> 1. Percolation rate in top 12 inches of soil is ��_1.'�-s_ pi <br /> Pcrcolatlon Rmc Gallons Ra1io of <br /> 2. Select allowable soil loading rate from table on p ge E-; in Minutesp�r Soil Tcxture per day�xr Absorption widih <br /> �'� gPd�f� fnch(MPI) squnre foot lo Rock Laycr <br /> Width <br /> 3. Calculate adsorption width ratio by dividing rock layer F����,�ne�o.� • c�us��,� _____ __.._ <br /> o.i�a s s��� i.zo i.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil load ng rate; o.��os•• FincSand•� o.�o Z.�o <br /> 6toIS Snnd Lnam 0.79 I.S2 <br /> 1.20 gpd/ftZ-t- � '-I . gpd/ftZ= � , !.. � ie�o�o �„�, 0.6o z.cx� <br /> �i�o as su��,��» o.so z.ao <br /> Check tliis value on page E-16. 46�a�, ClayLomn o.as z.�, <br /> � 60 l0 12tl Clay 0.24 S.IM) <br /> 4. Multiply adsorption width ratio by rock layer wi th to get s�oWe��nr� c�,y ...__ __.._ <br /> t2o••• <br /> required adsorption width; <br /> �?.T.,�x � � ft = ='�.�'� ft <br />