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1996-008247 (sewer & water)
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Bayside Road - (AKA: Co. Rd. 84)
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4080 Bayside Road - 06-117-23-14-0014
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1996-008247 (sewer & water)
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Last modified
8/22/2023 5:23:41 PM
Creation date
1/19/2016 1:38:29 PM
Metadata
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x Address Old
House Number
4080
Street Name
Bayside
Street Type
Road
Address
4080 Bayside Rd
Document Type
Permits/Inspections
PIN
0611723140014
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• ' MOUND DESIGN WORKSHEEI' <br /> (For Flows up to 1200 gpd) <br /> A. �.Qw Estimated Sewage Flow in Gallons per Day(gpd) <br /> Estimated �S� gpd N,�„� <br /> or measured - x 1.5 = - gpd. B�°�� �'�I �'P�II Type III �ry�rv <br /> 2 soo zu �ao b� <br /> B. SEPTTC TANK LIQUID VOLLTMES a bo�o 3°s° Z,s� '� <br /> 5 750 450 294 v�,� <br /> �.-�C[7C) c�� i1 �„�1 gdllOI1S a- JOGC7 �r����41�- �qb� !- � ov�"'i' � 6 900 525 332 � <br /> � 1050 600 370 ��'„�,. <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) � , ��� <br /> �� �� <br /> 1. Depth to restricting layer = a� -rc� .3v inches �f ��` �"""" <br /> s�� � � <br /> 2. Depth of percolation tests = 1 a �� inche `""m"' `D"m`' <br /> 3. Percolation rate � .� m i z�� �So �.�zs <br /> P 3 or 4 1,000 I,500 <br /> 4. Land slope 9 % s«6 i.sao 2.uo <br /> �a s z,000 3.000 <br /> ovc 9 See fig.C-6 (z 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required are of rock <br /> layer: A x 0.83 = <br /> �Sc� gpd x 0.83 sq. ft./gpd = ��sq. ft. <br /> 2_ Select width of rock layer (10 feet or less) _ /o ft. <br /> 3. Length of rock layer = area=width = Rock Bed <br /> (_.��sq. ft. -�- �ft. _�a ft. ti.ti.�.ti.ti.ti.ti.�.�.ti.ti.�.,,�,�.ti.ti <br /> �t���t•I•l.J.J.r•f•t•l.J•f•t.d.l. <br /> ti•ti•ti•ti•1•t.ti.ti.ti.1•ti•ti.ti•ti <br /> tiftifti�ti:ti=tifti�ti=ti�tifti�tirti:ti:ti:ti':ti idth 510 ft. <br /> �rtirti:tir�rti.�rtifti.tir�:•r•f.f.r.f. <br /> ,f,f,f,f,f,J f�f f f r�fti•ti•ti•ti•ti <br /> 1•t•J•J• <br /> E. ROCK VOLUME � Length --� <br /> I. Multiply rock area by rock depth to get cubic fe t of rock; <br /> a� sq. ft. x ./ O f f t. _�S� cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic y ds; <br /> S?_cu. ft. = 27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of ro in tons; <br /> �.�I cu. yd. x 1.4 ton/cu. yd. _ � tons. <br /> F. ADSORI'TION WIDTH t-,o A ,�i <br /> Abso �on 1Yidth Sinn Table <br /> 1. Percolation rate in top 12 inches of soil is�.n� mpi PeicolatlonRare �� a�d <br /> t,tu,uce,�,�, SoilTexture �,�R �,,m <br /> (mpil F�. .b.o.pea. <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand lzo i_oo <br /> � (o (� gpd/ft� 0.1 to� Sand 120 1.00 <br /> 0.1 to� Fine Sand*' 0.60 2.00 <br /> 6 to i� ndy Loam 0.79 1.�2 <br /> 3. Calculate adso tion width ratio b dividin rock la r -�b.co30_ Loam �,� 2.00 <br /> � y g �' 31 to 45 Silt Loam 0.50 2_40 <br /> loading rate of 1.20 g-pd/ft2 by allowable soil loading ate; ��o bo c�ay Loam o.4s 2.6� <br /> 61 t0 120 Clay 024 �.00 <br /> 1.20 �7C�/ff2= . �v gpd/ft� _ � ,00 Slower than 120 Cla -- - <br /> ••Soil havinK�OR or more of fine or verl'fuie sand. <br /> 4. Multiply adsorption width ratio by rock layer width get <br /> required adsorption width; <br /> �,00 x /v ft = ac�.c�ft <br /> I I <br />
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