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OSTP Pressure Distribution <br /> Minnesota Pollution • UNIVERSITY <br /> Des�gn Worksheet oF MiNNEsoTa �` � <br /> Control A enc -'��`:" <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perjoroted Laterals in system/zone: � ----_ <br /> (2 feet is min�mum ond 3 feet is maximum spacing) ""„'�„"""�„°`" <br /> 2. Select Perforation Spacing: 3.0 ft 11 ' � ,2`'S ' , � � - <br /> � <br /> Miiiimum <br /> '/."pe�lora[ions zpacetl 3'apart 1"-2'of rock j 2" <br /> 3. Setect Perjoration Diameter Size 7/32 in _ _ <br /> 6"of rock <br /> 4. Length of Loterals =Medi�Bed Length - 2 Feet. Pe,'°'a"°^����^9 ''° `°''' Pef'°�A"°°5��,<",,:= °3 <br /> 26 - 2ft = 24 ft Perforation can not be closer then 1 foot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Laterols (Line 4) by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spoces = 24 ft - �ft = �Spaces <br /> 6. Number of Perforotions per Lateral is equal to 1.0 ptus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Laterol = �Spaces + 1 = �Perfs. Per Lateral <br /> Check table below to verify the number of perforations per laterQl guarontees less than a 10%discharge variation. The va(ue is <br /> double if the a center manifo(d is used. <br /> Maximum Number of Perforatians Per Lat?ral tu Guarantee<10�Gisr_harge Yaration ' <br /> -- ;Incr�P:{loret:�x�z 7r3?I��ih Pertoracioas <br /> ; Pipe Dinr.�fer(Inihesl Perf��racic��Spaiing Pipe Cre^��ter (Incll�s) <br /> � Pe�tora��c�n tipacna.IF�tI 3 <br /> 1 1'•. 1�^. 2 t (f cet I t l'�': 1�^ 2 ; <br /> Z 10 13 1E 30 69 2 11 16 2f 3�i j F,° <br /> 2'^ $ 12 I 16 13 j 54 2'�: �1) �.� �n � ;7 !, F..� <br /> �_ <br /> 3 ; 9 12 � tb 25 5� 3 9 14 19 30 � h0 <br /> 3"16 Ir�ch Per'cKa;ions I $ Inch Pe�t�iratson> <br /> Fi�Diamrtrr�Ir�che>1 Perfora�on�paiing F'ipe Uar.ie;rr ilnrhe>1 <br /> F'e'f�ifnC:v�i`_pe�'�fi��IFa�t) � - ---�-,---- <br /> � � � �;-:��t�; T 2 � 3� iF�tl i f i 1�: I it? 2 i 3 <br /> � "t � 12 8 ! 26 � 4b ��7 2 j 21 � 33 �t 7�1 � 149 <br /> i- <br /> �i Y^. 12 I 17 2�4 �0 I 30 "1�= ?p 3p -ii E9�_1._3_5__�'. <br /> � 3 12 16 22 37 75 3 20 29 38 j 64 ! 128 ' <br /> 7• Tota(Number of Perforotions equals the Number of Perforations per Loteral (Line 6)muttiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> �Perf. Per Lateral X �Number of Perf. Laterals = 27 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforotion. Recommended value is 4-10 ft1 per perforation. P•�r�•"onDia°"���,°"", <br /> Does not app(y to At-Grades �a ft ve�ro.,no�o�,m.�.� <br /> � i ,,. '�,. - ,_ . <br /> Bed Area = Bed Width (ft)X Bed Length (ft) �.o• o+s o 4� 0.56 0�� <br /> 7.5 0.22 0.51 0.69 0.9 <br /> 10 ft X 26 ft = 260 ftZ Z.o° o:b 0.59 0� ,o, <br /> 2.5 0.29 0.65 O.B9 1.17 <br /> 7.0 0.32 0.72 0.98 1.28 <br /> Square Foot per Perforation =Bed Area divided by the Tota!Number of Perforations (Line 7). •.� o» o e� , ,� ,�� <br /> 5.0` 0.11 0.93 1.26 1.65 <br /> 260 ftZ = 27 rforations = 9.6 2 ,',�� �e�`����`h'�,b;��`°,�.;,�h <br /> pe ft /perforations DeRoraciom, <br /> Dwellinip wit�I/8 inC�p2Aoratior[� <br /> 9. Select Minimum Avera e Head: 1.0 ft 2��� a^��r�`sa�'hm`��'�'MS75 w;`h'��� <br /> g izh�o��<���h PtAo�a�pra <br /> 5�� lhher eStaWishmmcs and MSTS wit�I/8 inch <br /> pzrtoratbin <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br />