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OSTP Mound Design Wor sheet <br /> UNIVERSITY �` ` <br /> Minnesota Pollution 1'�� S�� e OF �INNESOTA � � <br /> Conirol Agency p ��- ��� <br /> 1. SYSTEM SlZING; ProjectlD: v 11.09.22 <br /> A. Design Ftow(Flow&Sof(- i.A): 750 �Po TABLE IXa <br /> B. Soil Loading Rate(Flow&5oi1-3.C): O.GO GPD/ft2 �OADIN RATES FOR DEiERMiNiNG BOTTOM ABSORPTION AREA <br /> AN A$SORPTION RATIOS USING?ERCOLATION TESTS <br /> C. DepLh to Limiting Condition: 1.0 ft 7reatn,enc t.erei c rUtmtM�evel A,A4,a, <br /> D.Percent Land Stope: 7,U % ; po�wia o�,a�ce "�Ot➢QO" �,�,d "bS"p°°" �,,,� <br /> � �� Area loa�r� Area tna�r�g <br /> Rate �pt� Rate �P� <br /> E. Design Media Loading Rate: 1.2 GPD/ft2 ' �,yyr�� �t'O �q�=3 �1O <br /> F.Mound Absorption Rvtio(Table IXa): 2.00 <�� - � _ � <br /> G.Design Contour Loading Rate: 12.0 GPDJft Q�t��' i2 � �_s a <br /> ;0 1.0 5{f sarcl 0.6 2 1 3.6 <br /> Tabfe I ���and roam re sa <br /> MUUNO CUt7TUUR LOApING RATES: :`���t5 0.)8 1.5 � 1.6 <br /> t.soawrod ' Toxture-da'ivad ��iwr ��Sto30 0.6 2 0.78 2 <br /> � � <br /> 7er<P.a*a 0� n�,y�yd absOrptian rati vaden �I.31to45 0.5 2A 0.�8 2 <br /> . Rit9: <br /> '4^o�toBQ OA5 2.6 0.6 2.6 <br /> -5�mp+ 1.G-t.E.2.9.2.d.?6 :t2 <br /> '-:6�to 12G - 5 0_3 5.3 <br /> 6t-i2C^,ipi n? '..0 <_it '»20 - - - - <br /> _i zu�,,,-' -5.rr :5' 'Systems wiCh vaiues are not Type I systems. Contour Lnading Rate(linear <br /> loadi�rate)is a recommended value. <br /> 2. DISPERSAL AAf01A SIZiNG <br /> A. Catcuiate Required Dispersal Bed Area:Design Flow (1.A):Design Media L ding Rate (1.E)=ftZ <br /> if a larger dispersal media area 750 GPD= 1.2 �po�ft2 = 625 ftZ <br /> is desired,enter size: �ftZ <br /> B. Catculate Dispersa!Sed Width:Contour Loading Rate (1.G)=Design Medi toading Rate (1.E)=Bed Width <br /> 12.0 ft s 1. gpd/ftZ = 10 ft <br /> C. Calcutate Disperwl Bed Length: Disperwi Bed Area (2.A):Bed Width (2. =Bed Length <br /> 625 ftZ : 10 rc = 63 ft <br /> D.Select Dispersal Media: <br /> E. If using a regisiered product,enter the Component Length: in: 12 = �{t <br /> F. If using a registered product,enter the Component WidLh: in: 12 = ��ft <br /> G.Number of Componenfs per Row=Bed Length (2.C)divided by Componen Length (4.J){Round up) <br /> � ft i � ft= �c ponenu/row <br /> H.Number of Rows =Bed Width {2.6)divided by Component Width {4.K)(Ro nd up) Note:CLR of f0.3 <br /> gaUft rewlts in 9 foot <br /> �just Contour Loadirtg Rate on Design Summary page until this number is whote number ���d <br /> �� ft� � ft= � orovs <br /> �_ Total Number of Components =Number of Components per Row X Numbe of Rows <br /> � X � _ �t mponenYs <br /> -- -.__._.._----------��._....------- -- , --_ <br /> � <br />