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( � <br /> i <br /> _::: OSTP Mound Design Work heet ��;� ��, <br /> UIViVERSITY ,F ��'z� <br /> Minnesota Pollut{on O �- ���-� <br /> ControlAgency >1 / Slope OF�INNESOTA �"'�Y,L�y <br /> 1. S1IS7EM SIZING: Project ID: v 11.09.22 <br /> A.Deslyo Flow(flow&5off- 1,A): 75Q GPD 'T'Ae�� �Xa <br /> B, Soi(tOpdipg Rote(Flow&Solt•3.C): �.6� GPD/(t2 �DAOIHG t TES FOR OEfERMINlNG SOTTpM AHSORP710N AREA <br /> ANO 950AP.T(ON RATt05 USIkG PEIiCOlAT10N TESTS <br /> C.Depth to Llmltlny tondttfonc 9.0 ft rresc+�,enc�evN c TraUaent Levet A,�•:,o, <br /> D.Fercent Larxl Sfope: 7,0 � PerColad Rdc� "�°" � "�'�a?+0" 7ibiiite <br /> Rrea loadint ea Load� �n <br /> (� Aete ���0� � Rate . �3'D <br /> E.Desfgn Media Loadl�y Rote: 1.2 GPD/ft2 ��R�� R'�O ���:� R'cr° <br /> F.Mound Absorptton Ratlo(Table iXa): 2.00 so.� . � . � <br /> G.Oeslgn Con[our Loadfny Rate: 12.0 GPD/ft °=io 5 t.2 � t.s t <br /> .tio5(Rr end 0.8 2 t 7.8 <br /> TeWel andbs I sara <br /> MOUN�CO?ITpUR LOADING RATES: to�5 OJe 1.6 1 �,g <br /> NqaSu�Od ToRtttre•dorivod C�t`'�r t61o30 0_8 2 0.78 2 <br /> Parc Rate � nw�x�d absprptton raUo LO��A� 3I to43 0.6 2A 0.78 2 <br /> Rato: <br /> 4olob0 OAS 2.6 O.b 1.8 <br /> =bOn�i 1.0.1.3.7.0.1.J.1.6 :t2 <br /> , 81 a�p - 6 0.3 6.3 <br /> Gi-124nryi �t S.O <_t2 >120 . _ . . <br /> :�zo rnp� .s.o' as� `Systems wSth thesa tues are not 7ype 7 systems. Contour Loading Rate(Iinear <br /> ! ding rate)ts a reconxirended value. <br /> 2. D15�ERSAL MEDIA SlZING <br /> A.Calculate Required Dispersaf Bed Areu:Deslqn Flow (i.A�-:Desfyn MedIQ L !ny Rate {1,E)=ft� <br /> If a Iarger dtspersal media area 750 GPD r 1.20 GPD/ft2 = 625 (�2 <br /> Ss destred,enter size: (��ft� <br /> l+ <br /> 8, Calculate Ofspersaf&ed 4Ytdth:Contour Loadfny Rate {t.G)a Design Med�a L dfng Rate (i.E)=Bed Wldth <br /> 12.0 Ft = 1.2 qPd/ft2 = 10 ft <br /> C. Catcutate Dispersa!Bed Lengtb: Disperwl f3ed Area (2,A):Ded Wfdth (2.6) Bed Length <br /> 625 fi� = 90 ft = 63 rt <br /> D.Seiect D)spersef INedla: <br /> E. If using a registered product,enter the Component Lengfh: !n e 12 = C-�(t <br /> F.U us4ag a regittered prak�ct,c�tar the Canponent Wtdth: ln s t2 = ��{� <br /> G.Number of Components per Row=8ed Lengtt� (2.t)dlvided by Compatent L nyth (4.J)(Round up) <br /> �� t[ t � ft= �com [slrow <br /> H.Number of Rows =Bed SY1dth (2.8)divided by Component Wldth (4.K)(Roun up) Note:CLR o(10.3 <br /> AdJust Contour toading Rate on Oestgn Summary page untii this number h a ote number 3a��ft resutts!n 9 fooi <br /> w)de bsd. <br /> � ft� � ft= � r <br /> �, 1"otvf 1Vumber ojComponents s Number of Compormnts per Row X Number o Rows <br /> � X � ' �com ents <br /> 6 I <br />