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2012-01003 (Septic)
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Last modified
8/22/2023 4:35:31 PM
Creation date
1/14/2016 11:46:58 AM
Metadata
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Template:
x Address Old
House Number
2380
Street Name
Abingdon
Street Type
Way
Address
2380 Abingdon Way
Document Type
Septic
PIN
0311723230016
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� ��-. =�T OSTP Mound Design 1A/orksheet --�. � <br /> Minnesota Pallution UNIVERSITY -�''�`' a=��`� <br /> >1% Stope OF MINNESOTA �'4�'r}��`�^��y��`` <br /> Control Agency �=`}'""-'`�- � <br /> � <br /> 1. SYSTEN►SIZING: Projc�t ID: v 11.09.22 <br /> A.Design Flow(Flow&Soil- 1.a�: �5o GPD TABLE IXa <br /> B.Sofl Loudirtg Rate(F(ow&Soi(-3.C): 0.60 GPD/ft2 LOADMG RATES FOR DEI'ERMUIING BOTTOM ABSORPTION AREA <br /> AND ABSOftPTION RATIOS USING PERGOLATION TESTS <br /> C.Depth to Limiting Cond�Non: 1.5 ft rreatmeM�m c rr�satmera�a a,a-z,s, <br /> D.Percent L.ond Slope: 16.0 � �►�e�o�� �e� na��ma �"� �u� <br /> tn�) � �e�o� � a�rn�n <br /> E.Design Medin Loading Rate: 9.2 GPD/ftZ ��rc�� � (e,a�'� � <br /> F.Mound Absorption Rot�o(Table IXa): 2.00 �� - � - � <br /> G.Des3gn Contour L�ding Rate: 12.0 GPD/ft °�to 5 �.� � �.e � <br /> 01 to 5(fi��� 0.6 2 1 1.6 <br /> Table t arsd fum <br /> A3dUND COMTOUR LQ!►QING RATES. 6 to�5 0.78 1.5 1 1.6 <br /> Id�asursd '" T9�cQp'e-dgri+nsd Contow' �6 to� 0.6 2 0.78 2 <br /> Parc Rate � mQtmd absorption ra' ����� 31 to 45 0.5 2.4 0.78 2 <br /> 46 to s0 0.45 2.6 OS 26 <br /> 560mpi t.o,1.3,2.0.2.4.2.6 �12 <br /> 61 to 120 . S 0.3 6.3 <br /> 61-120 mpi OR 5.0 ct2 >>20 - - - - <br /> z i zo mp� -S.o' cb' �Syscems with these vatues are not Type I systems. Contour L�ding Rate(linear <br /> loadir�rate)is a retomrrtended value. <br /> 2. DISPERSAL MEDIA SIZING <br /> A. Calculate Required Dispersol Beal Area:Design Flow (1.A):Design Medfa L�ding Rate (1.E)=ft2 <br /> if a larger dis{�rsal media area 750 GPD: 1.20 GPD/ftZ = 625 ft2 <br /> is desired,enter size: �ft� <br /> B. Calculate Di�rsal Bed Width:Contour LoQding Rate (1.G)f Design Adedia L�d�rrg Rate (1.E)=Bed�dth <br /> 12.0 ft :- 1.2 gpd/ttZ = 10 ft <br /> C. Calculate Di�rsal Bed Length: Dispersal Bed Areo (2.A)=Bed�dth (2.6)=8ed Lertgth <br /> 625 ftz : 10 ft = 63 ft <br /> D. Select Dispersa!Media: <br /> E. If using a registered product,enter the Com�rtent Length: �in= 12 = ��ft <br /> F. If using a registered product,enter the Component IAHdth: �in: 72 = ��ft <br /> G.Number of Components per Row m�d Length (2.Cj d9vided by Com�nt Length (4.J)(Round up) <br /> � ft � � ft= C�components/row <br /> H.Numt�r of Rows =Bed Width (2.6)divided by Component W�dth (4.K)(Round up) Note:CLR of 10.3 <br /> Adjust Contour Loading Rate on Desi�n 5ummary pa�e until this number is a whole num�r Qa1��rew(ts�n 9 f�t <br /> wlde bed. <br /> �� ft= C� ft � rows <br /> �, Totnl Number of Components =Number of Components per Row X Number of Rows <br /> � X C� �com�nents <br />
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