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1995-05-10 Septic System Design Report
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1995-05-10 Septic System Design Report
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5/27/2026 1:27:15 PM
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x Address Old
House Number
2660
Street Name
Fox
Street Type
Street
Address
2660 Fox Street
PIN
0411723420001
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— — 1'J <br />MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated 3V0 gpd (see pages D-7 or I-3, 4, 5) <br />or measured gpd. <br />B. SEPTIC TANKQUID VOLUMES <br />S ( /teao allons (see pages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />I. Depth to restricting layer = Z 3 inches <br />2. Depth of percolation tests = I Z- inches <br />3. Percolation rate Ld5, mpi <br />4. Land slope + 70 <br />D-7 <br />QtiWiD sl+�.aY M1O.4 . sa.ga.s .0 �. <br />oreeaws <br />S <br />C C � _ <br />> <br />am <br />m <br />�w tea <br />1 <br />.m <br />aeo <br />aH <br />am <br />are <br />r +•• <br />1 <br />• <br />ep <br />to <br />age <br />no <br />am <br />rs <br />C-3 <br />St/t:C t.UJ( CAPACITIES. IN 6alLOM! <br />„e" C....... <br />■rws a..rr <br />0—a m." <br />f07r 1wYA CY.7s. <br />MWt.L <br />. sgaw .s# <br />.Js <br />low. lose <br />late <br />s.. $ lots <br />Joss <br />... = a seat <br />goal <br />D. ROCK LAYER DLMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: A x 0.83 = <br />-30e gpd x 0.83 sq. ft./gpd =Z�'9 sq. ft. <br />2. Select width of rock layer (10 feet or less) _ ft. <br />3. Length of r ck layer = area + width = �� /o <br />z �g sq. ft. + 1 O ft. = Z-s ft.� Rock Bed <br />U. <br />adth VC <br />E. ROCK VOLUME Length <br />I. Multiply rock area by rock depth to get cubic feet of rock; Z 7 <br />Z4a sq. ft. x (__-_ ft. = K93 cu. ft. <br />2. Divide cu. f by 27 cu. ft./cu. d. to get cubic yards; <br />Zq � . cu. ft. + 27 = q, Z cu. yd. <br />3. Mull' Iy cubic yards by 1.4 to get weight of rock in tons; <br />J Z cu. yd. x 1.4 ton/cu. yd. = jjjqns. PLy b io 90 <br />i <br />. s ion I <br />F. ADSORPTION WIDTH <br />1. Percolation rate in top 12 inches of soil is ZO mpi <br />2. Select allowable soil loading rate from table on page E-16; <br />O gpd/ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft'-7 by allowable soil loading rate; <br />1.20 gpd/ft2+ ��gpd/ft2 = Z: O O <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />h_ x Z ft = z ft <br />E-16 <br />.W.r.1Mr41wlei/YyM rMta <br />am- <br />F. <br />o ..a <br />s n w <br />tea <br />I <br />—� <br />. ... <br />. 8. a..J <br />
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