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1995-08-04 Septic System Design Report
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1995-08-04 Septic System Design Report
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x Address Old
House Number
2340
Street Name
Fox
Street Type
Street
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2340 Fox Street
PIN
0311723320015
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a i yo ---, - -� `j 7 �Et t -A k(• 7 <br />• a MOULD DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated gpd <br />or measured x 1.5 = ;pd. <br />B. SEPTIC TXNK LIQUID VOLUMES <br />gallons <br />C. <br />5.� trk <br />r: 4{6 ,R i / IL/ /5 <br />Eurtn4w4 Sevage I3u..s in Galloes per day <br />(gpd).-Moer <br />ur Tr1+e i <br />T.P. Ili <br />1 <br />'rva 1I1 T.tr <br />Oe aroonu <br />IV <br />xn <br />: s <br />ISO <br />3 <br />430 <br />3W <br />zl8 <br />•c <br />.s <br />600 <br />I 375 <br />•• <br />I S <br />r•'a <br />! <br />730 <br />aA <br />21" <br />w <br />6 <br />9W <br />.•:3 <br />I 33z <br />*�• <br />IOU <br />600 <br />370 <br />3 <br />1=0 <br />673 <br />I WA <br />r1w. <br />SOILS (refer to site evaluation) <br />1. Depth to restricting layer = -1 -e y inches <br />stotn Two c...w-. • w.w i <br />i <br />••..at.+d atrwuw tryra...a <br />2. Depth of percolation tests = ? inches <br />3. Percoladon rate 21) •C- mpi <br />4. Land slope �. % •s, . <br />D. ROCK LAYER DD Ei 1SIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />laver: A x 0.83 = <br />7`x� gpd x 0.83 sq. ft./gpd = G30 sq. ft. <br />2. Select width of rock layer (10 feet or less) _ If ft. <br />3. Length of rock layer = area + width = g.�. �Ad <br />3c, sq. ft. + c, ft. _ ft. ,.,...,.,... •. •.. ,.,.,..,.,.;.,... fir.. t f <br />r•r•r•r•r•�'r,i,: r.r•r•r•I I.I.. <br />r•r•r•r•i��•r•r•I I•I•I•I•I r•r• <br />ti.,.�.,., ,.,.,.;.,.�.,.,.�.,., Vidth 510 ft. <br />♦.r•r.r•i:r.r.r•r r•r•r•rtirtii� � <br />E. ROCK VOLUME Length ---� <br />1 Multi ly rock area by rock depth to get cubic feet of rock• t, ' I <br />p _ , <br />4.3o sq. ft. x _ / ft. = 3c cu. ft. <br />2. Civide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />c� cu. ft. + 27 - � cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />cu. yd. x 1.4 ton/cu. yd. _ '-1 tons. <br />F. ADSORPTION WIDTH <br />1. Percolation rate in top 12 inches of soil is ?Lk 1-,.pi <br />L • ,:- /(o -- 36; P7/-,/ -, ) <br />2. Select allowable soil loading rate from table; <br />r, , L gpd/ft' <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft-7 by allowable soil loading rate; <br />1.20gpd/ ftz+ � gpd /fe = - . C•c. . <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />z, or, x /t-)_ ft = , ft <br />.Absorption Width `_Wait Table <br />?a•_ia.anRattl <br />I Gaam <br />3auoo! I� <br />-imu... pw <br />Sou 7kutua <br />IW Lv pw <br />Abw,.-3•Kia +,C• 1 <br />( <br />inch u%l 1) <br />j"We rOp <br />w Rt k h•r. I <br />Ki+L1 <br />_ <br />Faster Urea 0.1 <br />Ca" Sand <br />- • <br />--• <br />0.1 to 3 <br />Saud <br />t.:0 <br />1.00 <br />0 1 to ! •• <br />Fir Sajndd <br />0.e0 <br />20o <br />�ZW <br />_ 16 b 30 <br />0.60 <br />31 10 a! <br />Sailer <br />0.50 <br />2.40 <br />46 to (jo <br />Car Loam <br />C.a! 2.57 <br />W io 1.0 <br />Ca- <br />C :a ! 0D <br />Slower t:-A n I <br />C.ay <br />( <br />• SGtI too toarsa• for lnsWlauon of a <br />standard systeta. <br />See 7010 0170 Subp z G. 3. Mp 2& <br />•• S.:,; having 30% W more of Ctr srd <br />plus .try rinrr sand. <br />• S-•tl tot) heavy tot ms1119146 u of a <br />standard .vitern. <br />See 7080.U'_ 10 Subp S.A. pegs 33. <br />
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