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<br />SEPTIC TANK VOi.i !Mi
<br />;2. (L 13::cQ gallon:-,
<br />SOILS (Site cv,1l11atH111 d.11.1)
<br />U('pth to rl'stnctmg layl'r
<br />IVL1x1111t1m dl'pth ol system C -:\ ft
<br />'-i \ I
<br />I , l
<br />Jt-l'1 Texture _k,_~ ______ Percolation rail'
<br />ssr l1~1-sq ft/ gpd
<br />TRENCH BOTTOM AREA
<br />l,•,·I
<br />It•,•!
<br />Ml'l
<br />H For trenches with 6 inches of rock below the pipe:
<br />A x F = __ x __ = __ sq ft of bottom area
<br />I. For trenches with 12 inches of rock below the pipe:
<br />A x F x 0.8 = __ x __ x 0.8 = ____ sq ft of bottom area
<br />J. For trenches with 18 inches of rock belov,1 the pipe:
<br />A x F x 0.66 = __ x __ x 0.66 = __ sq ft of bottom area
<br />K. For trend1es with 24 inches of rock below the pipe:
<br />A x F x 0.6 = ___ x __ x 0.6 =-. ___ sq ft ol bottom area
<br />BED BOTTOM AREA
<br />L For Cravity beds with 6 or 12 inches of rock below the pipe;
<br />1.5 x A x F = 1.5 x __ x __ = __ sq ft of bottom area
<br />For Pressure beds with 6 or 12 inches of rock below the pipe;
<br />Ax F = __ x __ = __ sq ft of bottom area
<br />ROCK VOLUME IN CU IT
<br />M. Rock depth below distribution pipe plus 0.5 foot times bottom area:
<br />M =Rock depth+ 6 inches x Area (H,I,J,L,K)
<br />( __ + 05 ft) x __ = __ cu ft
<br />ROCK VOLUME IN CU YDS
<br />N Volume in cu ft divided by 27
<br />0.
<br />M + 27 == cu yds _ + 27 = ___ cu yds
<br />ROCK WEIGHT
<br />Cubic yards times 1.4 = tons
<br />N x 1.4 = tons X 1.4 =
<br />DISTRIBUTION
<br />tons
<br />(Check one based on slope) __ Bed ( < 6% slope)
<br />Trend1es __ Drop boxes (any slope) __ Distribution box(< 3%)
<br />SYSTEM LENGTH
<br />P. Select width= ft
<br />Q Divide bottom area by width: (H, I, J, or K) + P = lineal feet
<br />~ +IEL ==_lineal feet
<br />Gravelless Pipe
<br />( 10" :A x F + 3)= Lineal Feet ( 8" :A x F + 2)= Lineal Feet
<br />Chamber (A x F + width of chamber)
<br />1..SC_xlJO_ + l= 1it2linl'al f,,ct
<br />LAWN AREA
<br />R Sekel trench spacing, center to center = It-ct
<br />S Multiply tr('nch spacing by lineal feet Rx()"' sq ft ol lawn are;,
<br />X "(j Ii
<br />LA YOLJT (Us" <>Iller :-,id,,)
<br />',<'I<', t .111 ,ipprnpriat<-scak; one squ,11,· ic,•t
<br />' ',how jl<'rti1w11t prop<'rly houndarie:-,, nght-llf· wiiy, e;i,-.,•n1<·11t:-.
<br />1 Shu,"' locat1on nf house, g<1rag(', driVP\v;1v, <lnd ;di nthe 1
<br />1111p111v,•11wnb, ,•nsting or pr()po:-,,•d
<br />·l '.;huw lo,·.it1tl11 and layout ot :-,ewag,, ln·at111<·11t :,)'Skni
<br />~ Sl1llw fl)cation of water supply well. ·
<br />11 D1nwnsion all Sl't backs and separation distances
<br />Lot 6
<br />I ,1m1;11,·,I \1·w.q•, 11,n, 111 <lal1011'.I-1wr II· _ _.,y (~pd)
<br />N11111hn
<br />of 1,,11 I I \'fll II l\-pc 111 Tvp,· 1v Hcdr,111111, -11XI .1 "}", . ~---,l \(I llkl 118 C'.l.)'i .. ,
<br /><i<kl q-, 15<, th'"
<br />7\0 4\(1 294 ,·.:ilu(',
<br />" 'HXI \)\ 1~) "' Iii('
<br />J(J",(I h(XI .no ,111.,,
<br />~ I :'(kl '17\ 408 1nlu1nn,
<br />N11111hc1 M1111mum M1n11nun1 Sq11u Tank Caparitr with of l.1qu1d G~t,~l!" Bn.hornns Capacity Disposal (l~allonsl (fallon,J
<br />~
<br />2 or less 750 1.125
<br />:l or 4 1.000 1.500
<br />5 or 6 1.500 2,250
<br />7 or 8 2.000 3,000
<br />over 9 See fig. C-6 (X 1.5)
<br />'.-,.HI ChAr;Htt-11:-tu:, & Rt·t1um .. ,f An-"~ ftu Sc"'-'tt' Tn-.11tm1:nt
<br />l'nc,\lat1an R.;i.k 5<tu,,r..,f...,1 ~'-"--~
<br />Soil Texture f"l'"I f;~U.n f"'"d~, Mmult.--:, p,:•t tn<h ('<"Id~, ('<"• '"'i"~" 1mp1) h,
<br />Faster than 0.1" ~oarseSand ·-----
<br />0.1 to 5 Sand 0.83 1.20
<br />0.1 toS Fine Sand'" 1.67 0.60
<br />6 to 15 5andyl.oam L27 0.79
<br />16 to 30 Loam 1.67 0.60
<br />31 to 45 Silt Loam· 2.00 050
<br />46 to 60 Clat Loam 2.20 0.45
<br />Slower than 60"'".., lay ---(0.24)
<br />• Snil too co.:.n-c for sewagt.-tre4'.tmenl.
<br />U:.e S\'!>1.t.'ms (u,.-rapidlv ~ablt' soils.
<br />-Soil h'aving S(n, or mo~ o( (m~ or very lint' sand
<br />..... Soil with too high a percentage of day for
<br />installation o( a.n Jngmund standard system.
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