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/\
<br />(
<br />I l ( )\,\I
<br />(lr nH',lSllrl'd
<br />MOUND DESICN WOI0,~111 I
<br />(I ,If I lnw•, IIJ' 1 .. I '{)(l )'.j'•l I
<br />X Is gpd
<br />SEPT]( TANK U<JUID VOLUMFS
<br />~ e__ \;>e() ga lions
<br />S, )I LS (reler to site evaluat1on)
<br />l Depth to restricting layer = M-mdw:--Z__h_f eet
<br />2 Depth of percolation tests = I 2 mches
<br />3 Text1.ire __ {o~JV\ Percolation rate ;2~--.::12 mp1
<br />4 Land slope 6 %
<br />t-1urrtoo ,,1
<br />Ho:Ju,.,nn
<br />1 • .,,: ..... ,,
<br />. ---;-:;---_
<br />I ,w11;4.1<,I \,wa1:< I-lows m Gall ·--
<br />, _lK!ld) "'" 11<• ,ta,
<br />t ✓,unl,o I l)'fl( I l\,)t O TyPc 01 --1~~~
<br />11f . rv
<br />i'kYhm,~ j ~I----1-----l_
<br />U5 180 ·-···-.
<br />i I l 4')()
<br />, / 1m
<br />I /VI
<br />,, I 9CXI
<br />10:;<1 I
<br />I )(X) I
<br />' i
<br />'(X)
<br />.17~
<br />4~ n.~
<br />600
<br />67~
<br />218
<br />256
<br />294
<br />332
<br />370
<br />I 408
<br />~lK Tan.St ·--acioe,(•ra.Uoas1
<br />V11n1mwu I~ UlfWd apaaty wtth
<br />( · .l.,uc11v i:ub.a.,::c dnpouJ
<br />1;\Q
<br />1()0)
<br />1)00
<br />1001
<br />112\
<br />1500
<br />:!ljO
<br />)000
<br />W<I_.
<br />or lhc
<br />vi.Jue,
<br />"'
<br />I l)lX I
<br />llo.
<br />' Ill
<br />; colunu1,
<br />Ltqwdap,,..:m
<br />Wt(h disrou.1&
<br />1iftins.io::
<br />D. R(X'K LA YER DIMENSIONS
<br />L
<br />2.
<br />3
<br />Multiply flow rate by 0.83 to obtain required area of rock layer: Ax 0.83 =
<br />ci2 gpd x 0.83 sq. ft./ gpd = 6~q. ft.
<br />Select width of rock layer (max 10· if <120 mpi max 5') = /D ft.
<br />L.ength of rock layer= area-;-vhdth = ~~o':a=~-~,-~:::~~--,~::.::,:§·Ji·,-,,c;;~Q:~•.e~,·~~~·;E•:~~~~;""?;;:;-TrE':0~9:;,:.P:.:,).
<br />_ 630 sq. ft.-;-/C ft.= -6_3 __ ft :<JtD.~-~-t.t.:,.•<1t_}.£rll_~~p
<br />0
<br />Qf
<br />0
<br />~ ?]:':~~~~'.-_. !::~-.:::;:)~; ~ '-:'. _'-;'. ~ ~vv ~v• • ·o· ' -~ . " . •r:,_,. .• ···c:·~uf>~'i ~~~:c:;:: ~ 6.;."0'6,Pt>·o6W;»UAi~~:.:~:o t~
<br />~,.~,L~ngth -b 3 rt ·
<br />E. ROCK VOLUME
<br />Width (0 ft
<br /><120mpi <10'
<br />>120mpi<5'
<br />l. Multiply rock area by rock depth to get cubic feet of rock; __ sq. ft. x __
<br />ft. = --cu. ft:
<br />2. Divide cu. ft. by 27 cu. ft./ cu. yd. to get cubic yards;
<br />_cu.ft -;-27=~.yd.
<br />3. Multiply cubic yards ·by 1.4 to get weight of rockin tons; __ cu. yd. x 1.4
<br />ton/ cu. yd. = ..33. tons.
<br />F. ABSORPTION \VIDTH
<br />Absorption Width Sizing Table L
<br />2.
<br />,
<br />,)
<br />Percolation ratp in top 12 inches of soil is; .f:?.~pi
<br />Texture _jpz ~ Pacoluioa lutc.m
<br />. '--=---\,~--MinulC:S per loch
<br />Select allowable soil loading rate from tablv,
<br />D. b gpd/ff'
<br />(MPI)
<br />F:utcr than O 1
<br />0 l to '.'I
<br />0 I to "I
<br />6 (Q 15
<br />16 lO j(J
<br />31 10 4~
<br />46 to 6-0
<br />6010 110 C:akubte ;1d:,nrplion widtJ1 ratio hv dl\ 1din;: r,,, k Liver
<br />l\)ad111r r.,1i-\l) l :(I gpd/ft2 by allov,•,d,1(' :,,.11l l,,,idrng rate,
<br />Slo~ llu:n l.1t1
<br />l 20 gpd / f(' -0 .6, ,\~p, 1 t t 2_-c:<::J
<br />\111ltij>I\ ,H}'"ll'<J•lli 1-.1,l1h 1,il1,1h\ 1,,,' ,.'\•' l',1,1:i, ,, ,:,·1
<br />l•'•j\ll)1•,; ,J(; ·>lj•\J()J, \','ldtli
<br />l _____ -------------------------~~-~ --~{) r, 20 r 1
<br />! Gz.11005
<br />Soil Torun I pa day per
<br />squ..:t.rr foot
<br />C.c.:trSt: Sand 1.20
<br />S>nd 1.20
<br />Frnc S:ind 0.60
<br />S>ndi· l.=m 0.79
<br />Lo= 0.60
<br />S,h l.-02Ill 0.50
<br />C 12,· L<.Um 04~
<br />(-by 0.24
<br /><'l:l\ 0.)0
<br />~o of Abso:pooo
<br />wid<hto Rod
<br />Liycr Width
<br />LOO
<br />I 00
<br />?.00
<br />1.52
<br />2.00
<br />:!.40
<br />2 67
<br />5 00
<br />h(U
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