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· PRESSURE DISTRIBUTION SYSTEM <br />1. Select number of perforated laterals .S. <br />2. Select perforation spacing = 2/;--feet <br />3. Since perforations should not be placed closer.than 1 ft. to <br />the edge of the rock layer (see diagram), subtract 2 ft. from <br />th.e rock _layer length. <br />Rocxl=gth -2 ft.= 43 feet <br />4. Determine the number of spaces between perforations. <br />Divide the length above by perforation spacing and round <br />down to nearest whole number. <br />I <br />! <br />Length perf. spacing= 4-8' ft.+ 2 .. ~ ft.= l; spaces <br />. (#3) . (#2) <br />S. Number of perforations is equal to one plus the number of <br />perforation spaces . <br />/9· spaces+ 1 = 2-o perforations per lateral <br />6. Multiply perforations per lateral by number of laterals to <br />get total number of perforations. · · <br />t' Cleon Sond Lcytt <br />., · .. -:: . . : . . . ; <br />1 o~:~: Soll -~;.,;y S:o,;;;~ ;,- <br />a.,o ... PIOCU1<1 Sond L.cy., <br />TABLE OF PERFORATION DISCHARGES IN GPM <br />Head Perforation di.imeter (inches) <br />7 / 'Sl 'I. <br />1.0a 0.56 0.74 ' ! <br />1.5 0.69 0.90 <br />2.0b 0.&) 1.04 <br />2.5 0.89 1.17 <br />3.0 0.98 1.28 <br />4.0 1.13 1.47 <br />5.0 1.26 1.65 <br />a Use 1.0 foot of head for residential systems. <br />bUse 2.0 feet of head for other establishments <br />Table 2 ~ -z,o -b . <br />Werals X pens/lateral -__ perforations M:iximum :a.llow:abl<! number o( qu:itcr inch penor.ations per <br />l:atcnl to gwa.-:antce <10% Disch:al"l!e v:ariat.ion <br />7. Determine required flow rate by multiplying <br />number of perforations by flow.per perforation <br />h6 . C1::L -/JC <br />. pm~ X gpm/pe:rf -...:r.z.. gpm. <br />perlonU-'!""'l"C <br />. ((..et) <br />2.5 <br />3.0 <br />3.3 <br />4.0 <br />5.0 <br />· · -8. · If laterals are connected fo header pipe as shown on upper <br />example,._select mini.mum required lateral diameter from <br />table 2; enter table with perforation spacing and number <br />of perforations per lateral. Select minimum diameter for <br />perforated lateral = '2-inches <br />i· <br />. 9. If perforated lateral system is attached to manifold pipe near <br />the center, as in lower example, perforated lateral length and <br />numper of perforations per lateral will be approximately one <br />half of that in # 6. Using these values, select minimum <br />diameter for perforated lateral from table 2 <br />perforated lateral := ""2-· inches <br />1.25 inch I 1.5 inch I <br />14 18 <br />13 17 <br />12 16 <br />11 15 <br />10 14 <br />~ .. "(_,,_, .. ,.,.,. "~ ..... ~..,... ___ ---- <br />2.0 inch <br />28 <br />26 <br />25 <br />23 <br />22