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~'rJ.VUJ.'1J-,t _,,_,.,__._, ___ . ·· -------
<br />(For Flows up to 1200 gpd)
<br />A. FLOW Estimau:d Sewage Flows in Ga.Jiau per da
<br />Estimated .(bco gpd (see pages D-7 or I-3, 4, 5) (gpd) y
<br />1-lumbct
<br />or measured gpd x 1.5 = of Type! Type 11 Type III Type Bedrooms IV
<br />2 300 225 180
<br />B. SEPTIC TANK LIQUID VOLU1vfES 3 450 300 21& ~
<br />4 600 375 256 ollbo 2-c=co gallons (see pages C-3 or C-5) 5 750 450 294
<br />,.._
<br />ia 6 --900 525 332 1u:,L 7 10:50 600 370
<br />SOILS (refer to site evaluation)
<br />8 1200 675 403 m
<br />C.
<br />... _
<br />24 1. Depth to restricting layer= inches Scpu: T•alt C•paciLics, ia ,,.11o.,s
<br />)2-Number of Minimum Liquid Liquid =p,,cuy wu.t, 2. Depth of percolation tests= inches· Bcdrocms C..,..:ity 1:a.rl>aee dispoo.al
<br />3. Percolation rate }-::? mpi lo,lcu 750 112.S 3 C,4 lea> 1500
<br />4. Land slope 3 % '4or6 1500 2250 7, g oc9 :la)) XO)
<br />.,_9
<br />' '
<br />D. ROCKLAYERDIMENSION~ -.
<br />1. Multiply flow rate by~ to obtain required area of rock
<br />c::,_.'2,"l
<br />layer: Daily Flow X me= . , ::s ~ gpd x.l::i=OQ sq. ft./ gpd = .2Q2_ sq. ft. .
<br />2. Select ·width of rock layer (10 feet or less) = to ft.
<br />3. Length of rock layer= Area+ Width=
<br />5"00 sq. ft.+ )o ft.= Sb ft. Rock Bed
<br />• ,..---:.,,-.--: ..• ,,.. .. .,/! .·;.-::.-:;. •• •• :;.:_. ..... : ..,. .·;. :..,. I . ......... .,, .... , ............................ ....... ~ ............ ~ .... ,,.. ........... ~ ....... Width 510ft. ~ ........... , ............ , .. -,. ........................ ....... ,,.. ............. ,,.. ............. ~~ ..... I ~-~-~-,-,., . .,, .. ,.~-~--.-~-,-,-~-
<br />E. ROCK VOLUME -~-~-~-.--~-~----~·~-~-~-~·~·~-.. Length
<br />1. Multiply rock area by rock depth to get cubic feet of rock;
<br />5co sq. ft. x _J_ ft. ~ ·SD::,cu. ft.
<br />2.. Divide cu. ft. by 27 cu. ft./ cu. yd.-to get cubic yards;
<br />' · .$ot.:, cu. ft. + 27 = · lj cu. :yd. . .
<br />3. MulK cubic yarc:15 by·1._4 to get weight of ~oc~ in tons;
<br />cu. yd. x 1.4 ton/ cu. yd. = TI_ tons.. .
<br />..
<br />F. ADSOI:<-PTION WIDTH ·
<br />1. .Percolation rate in top 12 inches of S-Oil is /3: mpi _ .Absorptlon Width Slzlng T:ible
<br />2. ·Sele~ allowable soil loading rate from table ·on_ page E-:-;·.
<br />. . -e>,7f gpd/ft2 <\·~--· ~:_~-
<br />3. Calculate adsorption width ratio-by dividing rock layer· -
<br />loading rate of 1.20 gpd/ ft2 by allowable soil loading rate;
<br />·· 1.20 gpd/ft2+ o(!f gpd/ft2= /457-.. · . .
<br />. Check this value_on_page E-16. _. . . ,. .
<br />4. Multiply adsorption width ratio by rock fayer width to get·
<br />required adsorption width; · ·· -
<br />; lo X /,S-Z.-ft = /s ft
<br />Pel,:ollltioa Rm
<br />inMinuceapcr
<br />. fndl (MPI)
<br />Futcrthan 0.1 '
<br />0.110 5
<br />0.) 10 5 ••
<br />61015
<br />l61030--
<br />311045
<br />461060
<br />60,ro 120.
<br />Slowl:r than
<br />r20-•
<br />Soil Tc:uure
<br />CooneS.u>d
<br />Sand
<br />F"mcSand ••
<br />,_S&ndy_l..oam
<br />Loam
<br />Sill Loam
<br />Clayl.oun.
<br />Oay
<br />Oay
<br />G.allons Jtwoo(
<br />pcrdlly pa Ahsa-plion width
<br />sqwire(oot 10Rockuycr
<br />W"Jdrh
<br />--1.20 : 1.00
<br />~ 2.00
<br /><OD 1
<br />2.00
<br />0..50 2.40
<br />0.45 ·U,1
<br />0.24 : S.00 --
<br />I
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