Laserfiche WebLink
NIOUND DESIGN WORKSH.Et:.1 <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated \-Z..0:::::> gpd (see pages D-7 or I-3, 4, 5) <br />or measured gpdx1.S = <br />B. SEPTIC TANK UQUID VOLUMES <br />3cx::o gallons (see pages C-3 or C-5) <br />C. SOILS (refer to site evaluation) 22\--1. Depth to restricting layer= inches <br />17 2. Depth of percolation tests= inches <br />3. Percolation rate /4 rnpi <br />4 .. Land slope ,u;> % -. , <br />' <br />D. ROCK LAYER DIMENSIONS o. 9 5 .. <br />1. Multiply ~ow rate by~io' obtain required area of rock <br />layer:Da1ly Flow x ~ = · · <br />I 'Zou gpd x~~·~cf. ft./ gpd ::; l6C:C:> sq. ft. <br />2. Select width of rock layer (10 feet or less)= ID ft. <br />3. Length pf rock layer= Area+ Width= <br />·1000 sq. ft.+ Io ft.= l-OS ft. <br />E. ROCK VOLUME . . <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />I O.QQ_ sq. ft. X _J_ ft. ~ tococu. ft. . . . <br />2.. Divide cu. ft by 27 cu. ft./ cu_. yd: to get cubic yards; <br />\ooo cu. ft + 2:7 = ·371 cu. y'<l. <br />3. • Multiply cubic yards by .. 1.4 to get weight of rock.in tons; <br />'TI_ cu. yd. x l.4 ton/cu. yd. = 5 2-tons .. · · · . <br />F. ADSORPTION WIDTII · <br />Estimated Sewage Flows in Gall0CU per day <br />(gpd) <br />Nwnbc:r <br />o( Type! Type II Type III 1w Bedroom~ <br />2 300 225 180 <br />3 450 300 218 011, <br />4 600 375 256 oCll>o <br />s 75-0 450 294 ...... <br />ia 6 900 525 332 ~I. 7 1050 6CO 370 <br />8 1200 675 408 !II <br />calumm <br />Septic: T ... k C•pacW,,., ;,. &•U..... <br />Numoc,o( Mini.mum Wquid Wquid c:apacity wiu, <br />Bedrooms Copaci,y 1:a.tbacc di,po.al <br />l or less 750 1125 <br />3 or4 lOXl 1500 <br />4ot6 1500 22.50 <br />7, & or9 200) ~ ,,_9 - <br />Rock Bed <br />---Length <br />1. -Percolation rate in top 12 inches of soil is \A:· .. m_ pi .· . .Absorption Width Sizing Table <br />.l'erc:olatioa R.a&e Gallons R.1lio of <br />2. ·Selectallowa~lesoillo~~a;~J; table·o~-!~:!·e~:.{.-· "'r:~h Soi1Te=e ~:,: ~=~~ <br />3. Calculate adsorption width ratio-by dividing rock layer·· Puter!hlino.1 • u=seSand -. - <br />0.1 IO 5 Sand 1.20 . 1.00 loading rate of 1.20 gpd/ ft2 by allowable soil loading rate; 0.1 tos-F"mcsanc1 •• ~~ ~ <br />· 1.20 gpd/ft2+ 01-?f gpd/ft'-= . /,5-'L · .. · . 1~~~----~ a.~ ----2.00 <br />31 to 45 Silt Loam O..SO 2.40 : · . Check this value.o·n_page E-16. _. . , . . ,, _ .. 461060 etay1..oiun· · o.4s -2.61 · 60·. IO 1:20. Oay 0.24 S.00 <br />4. Multiply adsorption width ratio by rock fayer width to ·get' s~ aay --required adsorption width;··· .. -. . ..._ _______ __._ __ ..._ ___ _ <br />; 'J;5-z_x / D ft =)S,2-ft <br />I