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A. Determine pump capadtlr. <br />Gravity DisWbutlon <br />I. Minimum suSpoed is 600 gallons per hour (10 gyre) to may ahead of <br />water use rate. <br />2. Maximum suggested for delivery to a drop box of a home system is 2,7M <br />gallons per hour (45 gpm) to prevent build-up of pressure in drop box. <br />Press re Dbefttlaa <br />3. a. Select number of perforated laterals <br />b. Select perforation spacing • ft. <br />c. Subtract 2 ft. from the rock layer length. <br />- 2 ft. <br />d. Determine the number of spades between perforations. <br />Length pert. spacing =1c!` ft. <br />e. -J., spades * 1= .%- perforations/lateral <br />f. Multiply perforation per lateral by number of laterals to <br />Set total number of perforations. <br />x_ perforations. <br />g• = x , •s: z gpm <br />SELECTED PUMP CAPACITY 3 "")_ ape+ <br />D. Determine head requirements: <br />1. Elevation difference between pump and point of discharge. <br />_' feet <br />2. If pumping to a pressure distribution ,ystem, add five feet for pressure <br />required at manifold <br />r feet <br />3. Friction loss <br />a. Enter friction loss table with gym and pipe diameter. <br />Read friction loss in feet per 100 feet from table. <br />F.L. = . ;,; ft./100 ft of pipe <br />b. Determine total pipe length from pump to discharge <br />point. Add 25 percent to pipe kngth for fitting <br />loss, or use a fitting loss chart. Equivalent pipe <br />lenl,th - I M times pipe length = <br />_-/ s x 1.25 = /,`_ feet <br />c. Calculate total friction loss by multiplying <br />hkoon lag in ft/10D ft by equivalent pipe length. <br />Total frklbn loss = rr x .100 = feet <br />4. Total head required is the sum of elevation difference, v <br />special head requirements, and total friction Im. <br />(il (2) (30 <br />TOTAL HEAD r feet <br />C F"Mp selection <br />1. A pump must be selected to deliver at least gpm (Step A) <br />with at least ' .r' feet of total head (Step 8). <br />NO res�oMI M OF is POWO s t arwa <br />WM s.r uw <br />�romp <br />Mw R <br />TANIJIMPOWOM atOMCKA119t•M4M <br />OmwANOW rora�M <br />1/4 <br />FSOM <br />are <br />tars <br />1a <br />1.17 <br />IM <br />110 <br />M <br />IM <br />us <br />.t1r.1 �s b�sl anew tar wdinw w� <br />awls bat d W Ise i sMiM <br />hirteat 401sias <br />elasttaa DM111aaas <br />Iva 1) 5' <br />F-Ifr <br />13 lash 2A Imh 3A hub <br />On FAWW a OM Maisrs <br />4110 <br />12 <br />0 996 <br />0�2f <br />1i <br />1M <br />SA <br />*As <br />30 <br />M? <br />all <br />23 <br />3.73 <br />1.11 <br />0.16 <br />30 <br />S.23 <br />135 <br />t1.23 <br />40 <br />N <br />is <br />147fI.73 <br />3M <br />o <br />so <br />3.99 <br />ass <br />35 <br />4.76 <br />a70 <br />so <br />s.sf <br />aft <br />0 <br />