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G.' DOWNSLOPE DIKE WIDTH <br />1. If landslope is 3% or more, subtract rock layer width from <br />adsorption width to obtain minimum downslope dike toe for <br />absorption: <br />ft - _ ft = 1'7, feet -c}►"3 <br />2. Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation L-2 feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference <br />x . % + 100 = feet <br />c. Add depth of clean sand depth of clean sand for <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound <br />height at upslope edge of rock layer; <br />ft + 1 ft + 1 ft = -,,,z feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of ,. <br />e. Multiply dike multiplier by upslope mound height . <br />to get upslope dike width: 2 x = _Ifeet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height <br />.2 + S-feet <br />g. Enter table on page bottom with landslope and <br />downslope dike ratio. <br />Select dike multiplier of S <br />h. Multiply dike multiplier by downslope mound hei ht ,Q <br />to get downslope dike width: 1.9 x ;%c _ ' f <br />i. Compare the values of step G.1 and Step G-2.h. Select the <br />greater of the two values as the downslope dike width; <br />1_ feet 4a'.A�s t=nip. <br />j. Total mound width is the sum of upslope dike <br />width plus rock layer width plus downslope <br />"+ `�° - dike width; <br />1_ ft + 10 ft + 12-_ ft = L4 0feet up.. <br />k. Total mound length is the sum of upslope <br />dike width plus rock layer length plus <br />upslope dike width; <br />'I A. &eft+ )I f In <br />4 o t =Z- feet TOW4. <br />3:1 <br />11 <br />IMns <br />5:1 <br />&1 <br />7:1 <br />11 <br />11 <br />1,WPo <br />Gel <br />7.1 <br />w <br />s rfop <br />0 <br />1 <br />34 <br />3 <br />l0 <br />U7 <br />SA <br />536 <br />i0 <br />&x <br />7.0 <br />7M <br />10 <br />2.111 <br />to <br />3AS <br />SA <br />V6 <br />♦0 <br />SAS <br />7.0 <br />656 <br />l0 <br />743 <br />2 <br />3 <br />3.H <br />7A0 <br />&N <br />au <br />5-% <br />SAS <br />sAa <br />7.32 <br />lid <br />&86 <br />to <br />175 <br />3.70 <br />MY <br />W <br />l]6 <br />&A <br />S <br />L34 <br />3 73 <br />6.90 <br />• <br />5 <br />3AI <br />39 <br />5.70 <br />'s�1 <br />7AR/ <br />w <br />9.72 <br />Ian <br />2 <br />2u <br />�.3'jII� <br />A.17 <br />l00 <br />AJN <br />to <br />SA1 <br />11 • <br />LA{ <br />as <br />L <br />7 <br />3A0 <br />3 <br />3.26 <br />SSA <br />714 <br />7.0 <br />oil <br />I0U <br />12.07 <br />1373 <br />ZK - � <br />2.0 <br />_ <br />113 <br />3AS <br />170 <br />MI <br />0.6 <br />$71 <br />SAI <br />3 <br />3.16: <br />•.11 <br />SAD <br />43 <br />in <br />0.09 <br />II54 <br />13M <br />1191 <br />242 <br />is <br />3S7 <br />/.21 <br />40 <br />♦70 <br />s.M <br />5.12 <br />4A <br />l0 <br />2a <br />:A0 <br />l47 <br />10.0 <br />15.00 <br />IL92 <br />23M <br />236 <br />231 <br />2% <br />2s <br />3AS <br />3M <br />in <br />3.75 <br />u0 <br />U2 <br />4AS <br />{AI <br />11 <br />12 <br />SAS <br />7.15 <br />7.0 <br />11.11 <br />1230 <br />17AS <br />21A3 <br />30.43 <br />43.73 <br />226 <br />2.21 <br />273 <br />2.70 <br />3.23 <br />112 <br />3.61 <br />10 <br />1116 <br />3A0 <br />ut <br />40 <br />