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3. TRENCH OR BED BOTTOM AREA <br />H. For trenches with 6 inches of rock below me pipe: <br />AxF= _____ g~x ft 2 ----- <br />I. For trenches with 12 inches of rock below the pipe: <br />A x F x 0.8= 450 gpd x 2.2 ft/gpd x 0.8 = 792.0 <br />J. For trenches with 18 inches of rock below the pipe: <br />Ax F x 0.66= -----gpd x ___ ft/gpd x 0.66 = ----- <br />K. For trenches with 24 inches of rock below the pipe: <br />Ax F x 0.6= _____ gpd x ---ft/gpd x 0.6 = ----- <br />L. For gravity beds with 6 or 12 inches of rock below the pipe; <br />1.5 X AX F = 1.5 X _____ gpd X ft/gpd = <br />M. For pressure beds with 6 or 12 inches of rock below the pipe; <br />AxF= _____ gpdx ft/gpd = <br />4. DISTRIBUTION (Check all that apply) <br />Bed (<6% slope) <br />Trenches <br />Pressure <br />Drop Boxes (any slope) <br />Distribution Box (<3%) <br />Gravity <br />5. SYSTEM WIDTH, LENGTH AND VOLUME <br />M. Select width = -, -----ft <br />N. If using rock, divide bottom area by width: (H, I, J or K) divided by P = lineal feet I lft2, --ft = <br />Rock depth below distribution pipe plus 0.5 foot times bottom area: <br />(Rock depth + 0.5 foot x Area H, I, J, K, L} <br />(..___ ___ __,ft+ 0.5 ft) X <br />Volume in cubic yards = volume in cubic feet divided by 27 <br />I 27= <br />Weight of rock in tons = cubic yards times 1.4 <br />X 1.4= <br />--- <br />--- <br />yd3 <br />tons <br />0. If using 10" Gravelless Pipe, length= Flow (A) x Gravelless SSF (see figure D-9) <br />gpd X I I ft/gpd = <br />lineal feet ---- <br />ft2 = <br />lineal feet <br />P. If using a Chamber (H, I, J, K [based on height of chamber slats] divided by width of chamber in ft) I 792.0 lft2 I I 3.0 I ft = 264.0 lineal feet <br />7. LAWN AREA <br />Q. Select trench spacing, center to center= 6 lfeet <br />R. Multiply trench spacing by lineal feet R x Q = sq. ft. of lawn area <br />6 X 264.0 = 1584 ft 2 <br />ft 2 <br />ft 2 <br />ft2 <br />ft 2 <br />Rock <br />Chamber <br />Gravelless <br />Page 2 of 2