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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated gpd <br />or meat _d x 1.5 : — _ gpd. <br />B. SEPTIC TANK LIQUID VOLUMES <br />I-) 3,s0 . 1 -'Inn 0 b�s <br />C. SOILS (refer to site evaluation) <br />ptp� la inches <br />1. _ to rsstrfcdt►g layer = +,;�:,.� <br />2. of Pa' bests = _ inches <br />3. Perookdon raX mpi <br />4. band slope 4 % <br />"'o'IT.t I TM»tt ITy" III I1ypry <br />2 <br />}� <br />t0 <br />M <br />N <br />• <br />a* )" <br />W <br />h <br />•.� <br />s <br />no -on <br />I <br />3" <br />tao JIM <br />7 <br />too <br />iio <br />a eels <br />>+ f <br />• <br />_ <br />04 <br />�Ra <br />1a11 <br />lun <br />708 <br />VW 9 <br />2=66 <br />(A31 <br />D. ROCK LAYER DIIvQ1'NSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer. A x 0.83 = <br />_ISO , gpd x 0.83 sq. fL/gpd ■ �_ sq. ft. <br />2. Select width of rode layer (10 feet or less) ft. <br />3. Length of rock layer • area + width = Rock Bed <br />th $10 h. <br />E. ROCK VOLUME t-- Lao�~ <br />1. Multiply rodc arts by rock depth to get cubic feet of rock; <br />sq. ft. x "�.L ft. cu. it. <br />2. Divide cu. ft. by 27 cu. ft. /cu. yd. to get cubic yards; <br />cu. ft. + 27 = .,d 4 cu. yd. <br />3. Multiply vAk yards by 1A to get weight of rock in tons; <br />"_ cu. yd. x 1.4 ton/cu. yd. _ _-� -j tons. <br />F. <br />ADSOR3" LION WIDTii Ltd �c,u ►, <br />,� <br />M,,,�, <br />1. <br />Perco'ttior► rate in top 12 inches of soil is . Z.mpi <br />P. �.,. <br />Salk <br />4 <br />,.., <br />sail suau� �.� <br />W. <br />"Wo <br />.fto <br />Z <br />Aect allowable soil loading rate from table; <br />Fat o thtwo 0.1 <br />ne <br />1 <br />. S g'Pd / f P <br />0.1105 <br />s ni <br />mm sme• <br />Ila <br />OAo <br />2.00 <br />to 1s <br />UWr t.o.n► <br />0." <br />132 <br />3. <br />Calculate adsorption width ratio by dividing rock layer <br />;45 <br />s tasm <br />0500 <br />2.40 <br />loading rate of 110 gpd/ft2 by allowable soil loading rate; <br />61 a 6 0 <br />�t� <br />025 <br />.67 <br />23.00 <br />1.20 gpd/fts+,;�,� gpd/ft: _ <br />90wat 30 <br />— <br />— <br />•!r trR�aM w ww d M w.� Mc <br />4. <br />Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />aLk, x /0 ft= .eft <br />