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1996-07-10 Septic System Design Report
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1996-07-10 Septic System Design Report
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Last modified
12/11/2025 12:53:46 PM
Creation date
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x Address Old
House Number
2943
Street Name
Fairview
Street Type
Lane
Address
2943 Fairview Lane
PIN
0411723340008
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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated gpd <br />or measured - x 1.5 = - gpd- <br />B. SEPTIC TANK LIQUID VOLUMES <br />) -). --gallons <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = = : _ inches <br />2. Depth of percolation tests = _ ► inches <br />3. Percolation rate mpi <br />4. Land slope <br />Euimasad Sewate Flow in Gallons per Day (gpd) <br />N.ber <br />of <br />T)pe I <br />T)pe II <br />Type Ill <br />Tjn ry <br />BCAO Kna <br />2 <br />300 <br />225 <br />110 <br />em <br />3 <br />450 <br />300 <br />211 <br />ie <br />600 <br />375 <br />2.56 <br />.� <br />S <br />750 <br />450 <br />294 <br />6 <br />900 <br />523 <br />332 <br />7 <br />1060 <br />600 <br />370 <br />9 <br />12CO 1 <br />675 1 <br />408 <br />.mba <br />of <br />•._ <br />�. <br />c `-"... <br />Bedaoms <br />` Mo <br />2 or les <br />7S0 <br />1.125 <br />3 w 4 <br />1.000 <br />1.300 <br />5 a 6 <br />13W <br />1 <br />2.250 <br />7 act <br />2.000 <br />3.000 <br />o`a: 9 <br />Su Ri. C-b <br />(1 1.5) <br />D. ROCK LAYER DUVEENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: A x 0.83 = <br />1) S� gpd x 0.83 sq. ft./gpd = _ sq. ft. <br />2. Select width of rock layer (10 feet or less) _ = ft. <br />3. Length of rock layer = area y width = Rock Bed <br />ft. = ft. <br />idth 510 ft. <br />E. ROCK VOLUME ~- LAmptt -� <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />sq. ft. x ft. _ cu. ft. <br />2. Divide cu. ft. by 27 cu. ft. /cu. yd. to get cubic yards; <br />,' cu. ft. j 27 = D i cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />-1 cu. yd. x 1.4 ton / cu. yd. = -3,4_ tons. <br />F. ADSORPTION WIDTH L. o 4 „'1 <br />1. Percolation rate in top 12 inches of soil is ic .y mpi <br />2. Select allowable soil loading rate from table; <br />gpd/ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpd/ft2y gpd/fe = u <br />4. Multiply adsorption width ratio by rock layer width to g!t <br />required adsorption width; <br />:; x/ C,_ft= _ ft <br />VAdth Suvqit <br />Pwcolaaan Wr <br />.14 .,r_� <br />Soil Texture <br />SoeYutr <br />Qj" <br />�� <br />t` <br />_"Man <br />.-TO <br />Faster than 0.1 <br />Coarse Sand <br />110 <br />1.00 <br />0.1105 <br />Sand <br />1.20 <br />1.00 <br />0.1 to 5 <br />Fine Sand- <br />0.60 <br />2.00 <br />6 to 15 <br />Sandy loam <br />0.79 <br />1.52 <br />16 tc 30 <br />Loam <br />0.60 <br />2.00 <br />31 to 45 <br />Silt Loam <br />0-50 <br />2.40 <br />46 to 60 <br />1CJiu.zzth.an120 <br />Clav Loam <br />0.45 <br />2.67 <br />61 t0120 <br />Clay <br />0.24 <br />5.00 <br />I <br />Clay <br />- <br />- <br />es1 how" S0% o from at fw or vary rw rn1 <br />:�I <br />
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