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1993-06-28 Septic System Design Report
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1993-06-28 Septic System Design Report
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10/9/2025 3:13:34 PM
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x Address Old
House Number
550
Street Name
East Long Lake
Street Type
Road
Address
550 East Long Lake Road
PIN
3511823140002
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MOUND DESIGN WORKSHEET <br />�wPAJ.�Ctt�y.� (For Flows up to 1200 gpd) <br />A. FLOW '1-,5 C ,.V cv <br />Estimated Z110 gpd (see pages D-7 or 1-3,4, 5) <br />or measured gpd x 1.5 = <br />B. SEPTIC TANK LIQUID VOLUMES <br />- ) ;? 'c) gallons (sea pages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = a '' inches <br />2. Depth of percolation tests = inches <br />3. Percolation rate to . L, Inpi <br />4. Land slope % <br />Ealna..l Scwge Flow in CiWws per der <br />(90) <br />Nwnba <br />0( <br />Type 17hw <br />11 <br />Type III <br />Typo <br />1ledroome <br />v <br />2 <br />300 <br />US <br />110 <br />3 <br />ISO <br />300 <br />218 <br />4 <br />600 <br />373 <br />2% <br />ar <br />i <br />750 <br />ISO <br />294 <br />.ra. <br />6 <br />900 <br />325 <br />332 <br />'; L <br />7 <br />1 <br />1050 <br />1200 <br />600 <br />673 <br />370 <br />600 <br />.�. <br />$Wit Teak C.p.klm 1. pN . <br />�LCro-.ma <br />Cp.:o7 <br />e.b•e• Oi.p-A <br />Zak" <br />730 <br />1123 <br />3ae <br />IUO <br />13W <br />ea6 <br />1510 <br />2210 <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: Daily Flow x 0.83 = <br />2nn gpd x 0.83 sq. ft./god ei sq. ft.-t <br />2. Select width of rock layer (10 feet or less) = ft. <br />3. Length of rock layer = Area + Width = <br />sq. ft. + i L)- ft. _ 1� ft. <br />E. ROCK VOLUME <br />I. Multiply rock area by rock depth to get cubic feet of rock; <br />a= sq. ft. x 1. o f ft. _ cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />2&k cu. ft. + 27 = I) cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />li cu. yd. x 1.4 ton/cu. yd. = JS' tons. <br />F. ADSORPTION WIDTH 1.0 4 w? <br />1. Percolation rate in top 12 inches of soil is ' ., , L• mpi <br />2. Select allowable soil loading rate from table on page E-; <br />' Ligpd/ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpOW+ L4 gpd/ft2= p . t,Q . <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />2.L2 x gyp_ ft = 1.'2 ft <br />1 + . • a' 1 . <br />Rock Bed <br />� <br />4•♦333` ♦ ♦• ♦ ♦.- ♦ SIO R <br />►-- tln`a3 <br />Abarplion Wkkh SIB T►bb <br />Ibwledw Rom <br />111L11 IM►1) <br />Ciel3en <br />ey.01. i7�r <br />R"Or <br />� Ru! Lqw <br />VAM <br />I~ *Mal <br />CL SMd <br />- <br />-. <br />0.I IDS <br />SMd <br />1.30 <br />I.00 <br />0.10300 <br />Fire Swd " <br />0.60 <br />2.00 <br />61013 <br />Sadf lsr <br />0.79 <br />ISt <br />161030 <br />L00111 <br />040 <br />1" <br />31 10 4S <br />Sik Los" <br />0.30 <br />L40 <br />461060 <br />CM r L� <br />OAS <br />2.67 <br />600120 <br />CTOr <br />036 <br />SAO <br />Sumo 131M <br />a0y <br />- <br />- <br />120• <br />
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